Answer:
13
Step-by-step explanation:
8--5 = 8 + 5 = 13
x= 3+√5/4,3-√5/4
Step-by-step explanation:
1.In general, given ax^2+bx+c=0, there exists two solutions where:
x= -b+√b^2 - 4ac/2a, -b-√b^2-4ac/2a
2.In this case, a=4, b=-6 and c=1.
x=6+√(-6)^2-4×4/2×4, 6-√(-6)^2-4×4/2×4
3.Simplify.
x=6+2√5/8, 6-√5/8
4.Simplify solutions.
x=3+√5/4, 3-√5/4
The ordered pairs of the equation y = 3^x are (0,1), (1,3) and (2,9)
<h3>How to type the ordered pairs?</h3>
The equation is given as:
y = 3^x
Let x = 0, 1 and 2
y = 3^0 = 1
y = 3^1 = 3
y = 3^2 = 9
So, we have the following ordered pairs (0,1), (1,3) and (2,9)
Hence, the ordered pairs of the equation y = 3^x are (0,1), (1,3) and (2,9)
Read more about exponential functions at:
brainly.com/question/2456547
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Answer:
Step-by-step explanation:
The quadratic can be solved in a straightforward way:
This tells you that the solutions are ...
2i or -2i
__
For each root of "a", (x -a) is a factor. Thus the factors of the equation are ...
(x +2i)(x -2i)
Answer:
Step-by-step explanation:
Although I didn't get your question but I think you want to right intersection or union
PΠQ is equal to {5,6}
P union Q{3,4,5,6,}
