If m and n vary directly and m=3 when n=2, what is the value of m when n=4 no

Mathematics

1 answer:

nikklg [1K]3 years ago

7 0

Answer:

m = 6

Step-by-step explanation:

We know that m and n vary directly and that m = 3 when n = 2. How would we find m when n = 4? For starters, we can see that the value of n doubled (we know this because 2 doubled is 4), and since m and n vary directly, when n doubles, so does m so the answer is m = 3 * 2 = 6.

You might be interested in

Use the given graph. Determine the period of the function.

vichka [17]

The "period" of a repeating function is the change in x between consecutive identical values...in this case 3 units.

4 0

3 years ago

Read 2 more answers

What is y=-x+6?........

SIZIF [17.4K]

Answer:

Slope = -2/2 = -1

x-intercept = 6/1 = 6

y-intercept = 6/1 = 6

I wasn't sure what you really were asking for, so I did slope, x, and y.

8 0

3 years ago

single die is rolled twice. Find the probability of rolling an oddodd number the first time and a number greater than 33 the sec

givi [52]

Answer:

$\frac{1}{4}$

Step-by-step explanation:

A single die is rolled twice, we have to find the probability of rolling an odd number in first throw and a number greater than 3 in the second throw.

a) Rolling an Odd number in first throw

A die has total 6 possible outcomes, out of which 3 are odd numbers i.e. 1,3 and 5

So, total number of possible outcomes = 6

Total Favorable outcomes (Odd numbers) = 3

Probability is defined as the ratio of favorable outcomes to total number of outcomes. So,

The probability of rolling an odd number would be = $\frac{3}{6} = \frac{1}{2}$

b) Rolling a number greater than 3 in second throw

Here again total possible outcomes = 6

Favorable outcomes (Numbers greater than 3 are 4, 5 and 6) = 3

So,

The probability of rolling a number greater than 3 = $\frac{3}{6} = \frac{1}{2}$

These two events(rolls) are independent of each other, so the overall probability of both events occurring would be the product of individual probabilities.

So,

Probability of rolling an odd number the first time and a number greater than 3 the second time = $\frac{1}{2} \times \frac{1}{2} = \frac{1}{4}$