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Umnica [9.8K]
4 years ago
14

The elements in Groups 1 AU) and 7A(17) are all quite reactive. What is a major difference between them?

Chemistry
1 answer:
Yuliya22 [10]4 years ago
8 0

Explanation:

Elements of group 1A are known as alkali metals. Elements of this group are lithium, sodium, potassium, rubidium, cesium, and francium.

All these elements are metals and every element of this group has 1 valence electron. So, in order to attain stability they will readily lose their valence electron.

Hence, elements of group 1A are very reactive.

On the other hand, elements of group 7A are also known as halogen group. Elements of this group are fluorine, chlorine, bromine, iodine, and astatine.

All these elements are non-metals and every element of this group has 7 valence electrons. So, in order to completely fill their octet these elements gain 1 electron from a donor atom.

Therefore, these elements are alo reactive in nature.

But the major difference between elements of group 1A and group 7A is that elements of group 1A are metals but elements of group 7A are non-metals.    

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Which of these describes “Al”?
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What is the approximate mass of 72 cm3 of silver, if the density is 10.5 g/cm3?
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Answer:

<h3>The answer is 756 g</h3>

Explanation:

The mass of a substance when given the density and volume can be found by using the formula

<h3>mass = Density × volume</h3>

From the question

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We have

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We have the final answer as

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Which statement is correct abound chemical bonding in BF3 molecule O The molecule is not stable and hardly exist since the numbe
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The molecule is stable and can exist even though the number of valence electrons around central atom in the molecule are less than 8.

<h3>Is BF3 molecule stable or not?</h3>

BF3 molecule is a stable molecule because all the electrons present in the outermost shell of boron are covalently bonded with fluorine. Boron in BF3, three bonds is the maximum possible because boron only has 3 electrons to share.

So we can conclude that the molecule is stable and can exist even though the number of valence electrons around central atom in the molecule are less than 8.

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2 years ago
A reaction that is second-order in one reactant has a rate constant of 1 × 10–2 L/mol · s. If the initial concentration of the r
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Answer : It take time for the concentration to become 0.180 mol/L will be, 277.8 s

Explanation :

The integrated rate law equation for second order reaction follows:

k=\frac{1}{t}\left (\frac{1}{[A]}-\frac{1}{[A]_o}\right)

where,

k = rate constant = 1\times 10^{-2}mol/L.s

t = time taken  = ?

[A] = concentration of substance after time 't' = 0.180 mol/L

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Putting values in above equation, we get:

1\times 10^{-2}=\frac{1}{t}\left (\frac{1}{0.180}-\frac{1}{0.360}\right)

t=277.8s

Hence, it take time for the concentration to become 0.180 mol/L will be, 277.8 s

7 0
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