The bound state implies a net attractive force between the atoms. bond in which one or more electrons from one atom are removed and attached to another atom, resulting in positive and negative ions which attract each other. hope it helps

6 0

3 years ago

300 mL of 0.200 M Pb(NO3)2 is added to 200 mL of 0.0500 M NaCl(aq) at 25°C. Will a precipitate of PbCl2 form at 25 °C? Tip: You

Bas_tet [7]

Explanation:

It is given that volume of $Pb(NO_{3})_{2}$ is 300 mL and molarity is 0.200 M.

Volume of NaCl is 200 mL and molarity is 0.050 M.

The chemical reaction will be as follows.

$PbCl_{2}(s) \rightleftharpoons Pb^{2+}(aq) + 2Cl^{-}(aq)$

$K_{sp}$ for $PbCl_{2}$ is given as $1.7 \times 10^{-5}$ .

As, molarity is number of moles present in liter of solution.

Hence, moles of $Pb^{2+}$ (aq) will be calculated as follows.

moles of $Pb^{2+}$ (aq) = $0.300 L \times 0.200 M$

= 0.06 mol

$[Pb^{2+}]$ = $\frac{0.06 mol}{0.5 L}$

= 0.120 M

Mole of $Cl^{-}(aq)$ = $0.2 L \times 0.05 M$

= 0.010 M

Now, Q = $[Pb^{2+}][Cl^{-}]^{2}$

= $0.120 \times (0.010)^{2}$

= $1.2 \times 10^{-5}$

As, Q < $K_{sp}$ hence, there will be no formation of $PbCl_{2}$ precipitate.

3 0

3 years ago