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igor_vitrenko [27]
3 years ago
5

How would the pH value of an aqueous solution change, when the hydronium ion concentration is increased by a factor of 10?

Chemistry
1 answer:
Anna71 [15]3 years ago
4 0

Answer:

Increasing H⁺ by 10x => pH decreases by 1 unit

Explanation:

In general, adding H⁺ ions to any aqueous solution ALWAYS causes pH values to fall ( decrease ). Just as adding OH⁻ ions to an aqueous solution causes pH values to rise ( increase ).

Here's a simple calculation demonstrating this...

Given 0.01M HCl(aq) => 0.01M H⁺(aq) + Cl⁻(aq) => pH = -log(0.01) = 2.00

Increase [H⁺] by 10x => 0.10M H⁺(aq) => pH = -log[H⁺] = -log(0.10) = 1.00

Solution with higher H⁺ concentration shows <u>pH decreasing by 1 unit.</u>

______________________________________________________-

Just to support the above statement about adding OH⁻ ions showing an increase in pH values, the following is also provided FYI ..

Given 0.01M NaOH(aq) => 0.01M OH⁻(aq) + Na⁺(aq) => pOH = -log(0.01) = 2.00 => pH = 14 - pOH = 14 - 2 = 12

Increase [OH⁻] by 10x => 0.10M OH⁻(aq) => pOH = -log[OH⁻] = -log(0.10) = 1.00 => pH = 14 - pOH = 14 - 1 = 13

Increasing [OH⁻] by 10x => <u>increasing pH by 1 unit. </u>

Solution with higher H⁺ concentration shows pH decreasing by 1 unit.

______________________________________________________

Remember, for <u>any</u> aqueous solution ...

=> Adding H⁺   => always decreases pH

=> Adding OH⁻ => always increases pH

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Explanation:

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How much heat does a 100. g sample of copper absorb when its temperature increases by 30.0°C? The specific heat of copper is 0.3
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Answer:

\boxed {\boxed {\sf B. \ 1170 \ Joules }}

Explanation:

We are asked to find how much heat a sample of copper absorbs when the temperature is increased.

Since we know the mass, temperature increase, and specific heat capacity, we can use the following formula to calculate heat.

q= mc \Delta T

The mass of the copper sample is 100 grams, the temperature is changed or increased by 30.0 degrees Celsius, and the specific heat of copper is 0.39 Joules per gram degrees Celsius.

  • m= 100 g
  • c= 0.39 J/g °C
  • ΔT= 30.0 °C

Substitute the values into the formula.

q= (100 \ g )(0.39 \ J/g \textdegree C ) (30.0 \textdegree C )

Multiply the first two values. Note that the units of grams cancel.

q= 39 \ J/ \textdegree C (30.0 \textdegree C )

Multiply again, this time the units of degrees Celsius cancel.

q= 1170 \ J

The copper sample absorbs <u>1170 Joules</u> of heat and <u>Choice B </u>is correct.

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A chemical reaction takes place inside a flask submerged in a water bath. The water bath contains 8.10kg of water at 33.9 degree
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Answer:

The new temperature of the water bath 32.0°C.

Explanation:

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Initial temperature of the water = T_1=33.9^oC=33.9+273K=306.9 K

Final temperature of the water = T_2

Specific heat capacity of water under these conditions =  c = 4.18 J/gK

Amount of energy lost by water = -Q = -69.0 kJ = -69.0 × 1000 J

( 1kJ=1000 J)

Q=m\times c\times \Delta T=m\times c\times (T_2-T_1)

-69.0\times 1000 J=8100 g\times 4.18 J/g K\times (T_2-306.9 K)

-69,000.0 J=8100 g\times 4.18 J/g K\times (T_2-306.9 K)

T_2=304.86 K=304.86 -273^oC=31.86^oC\approx 32.0^oC

The new temperature of the water bath 32.0°C.

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