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hichkok12 [17]
3 years ago
11

*select all that apply

Mathematics
1 answer:
Stels [109]3 years ago
4 0
The answer to the question is the first, third and fifth
You might be interested in
A rectangle has a height of 3p^2+13p
frozen [14]

Answer:

-5p+7p^3

Step-by-step explanation: A rectangle has a height of 3p^2+13p

2

+13, p, squared, plus, 1 and a width of p^3+4p

3

+4p, cubed, plus, 4. we onnat

8 0
2 years ago
Solve for x in the equation x squared + 2 x + 1 = 17.
lbvjy [14]

Answer:

Step-by-step explanation:

x^2 + 2x + 1 = 17

x^2 + 2x = 17 - 1

x^2 + 2x = 16

x^2 + 2x + 1 = 16 + 1

(x + 1)(x + 1) = 17

(x + 1)^2 = 17

x + 1 = sqrt 17

x = -1 (+ - ) sqrt 17

x = -1 + sqrt 17 or x = -1 - sqrt 17 <===

7 0
3 years ago
To avoid detection at customs, a traveler places 6 narcotic tablets in a bottle containing 9 vitamin tablets that are similar in
Olenka [21]
The probability is 0.3, or 30%.

These are not independent events; one pill being chosen will affect the probability after that, as the pill will not be replaced before selecting the next one.

The probability of getting exactly 1 narcotic pill is given by:
(6/15)(9/14)(8/13) = 432/2730.  It does not matter what order the narcotic pill is in, the overall product will be the same.

The probability of getting exactly 2 narcotic pills is given by:
(6/15)(5/14)(9/13) = 270/2730.  Again, the order these are found in does not matter, as it is multiplication and will not change the product.

The probability of all 3 pills being narcotics is given by:
(6/15)(5/14)(4/13) = 120/2730.

Adding these three possibilities together, we have 822/2730 = 0.30.
8 0
3 years ago
Read 2 more answers
Darias bought 5 school binders that cost $8.00 per
Natalka [10]

Answer:

$25.44

Step-by-step explanation:

First, find the original cost of the binders:

5(8)

= $40

Find the cost with the 40% discount:

40(0.6)

= $24

Find the cost with the 6% sales tax:

24(1.06)

= $25.44

So, the total cost of the binders was $25.44

6 0
2 years ago
Simplify the expression <br> 49<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B2%7D%20" id="TexFormula1" title=" \frac{1}{
dimaraw [331]
To convert a mixed fraction into an improper fraction:

a\frac{b}{c} =\frac{(a\cdot c)+b}{c}

49 \frac{1}{2} = \frac{(49\cdot 2)+1}{2} = \frac{98 +1}{2} = \boxed{\bf{\frac{99}{2}}}
8 0
3 years ago
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