Solution :
We have to prove that (De-Morgan's law)
Let then
and
and so and
.
Thus, and so
Hence, .........(1)
Now we will show that
Let ⇒
Thus x is present neither in the set A nor in the set B, so by definition of the union of the sets, by definition of the complement.
and
Therefore, and we have
.............(2)
From (1) and (2),
Hence proved.
Answer:
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of , and a confidence level of
, we have the following confidence interval of proportions.
In which
is the estimate
z is the zscore that has a pvalue of , also called the critical value.
The standard error is:
90% confidence level critical value
So , z is the value of Z that has a pvalue of
, so
.
Estimate:
72 petty theft cases and finds 45 of these have gone unsolved.
So
Standard error:
Answer: