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3 years ago

Paul overdrew his bank account by $50, deposited $100, and wrote a check for

Mathematics

1 answer:

timurjin [86]3 years ago

7 0

Answer:

-50 + 100 - 30 = x

hope this helps

plz mark brainliest

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Help!! I cant figure this out for some reason

Thepotemich [5.8K]

Answer:

x³ - 6x² + 18x - 10

Step-by-step explanation:

(f - g)(x) = f(x) - g(x)

= x³ - 2x² + 12x - 6 - (4x² - 6x + 4)

= x³ - 2x² + 12x - 6 - 4x² + 6x - 4 ← collect like terms

= x³ - 6x² + 18x - 10

6 0

3 years ago

There are 10 students in class and the number of siblings in their families are given by {1,1,1,1,2,3,3,4,4,4}. Consider the exp

Svetllana [295]

Answer:

a. Check the attached image

b. The Pr(Y > 2) = ½

c. The mean is 2.4

d. The standard deviation is: 2.72

e. The exact value is 1 because it is certain from the given data that any probability will fall within that range.

Step-by-step explanation:

a. An image showing the step by step solution is attached.

b. P(Y > 2) = P(3) + P(4)

= 2/10 + 3/10 = 5/10 = ½

c. The mean is 2.4

d. The standard deviation is: 2.72

e. Check the attached image for the steps.

7 0

3 years ago

Ax-c=2x+5 solve for x

Dmitriy789 [7]

Ax - c = 2x + 5
ax - c + c = 2x + 5 + c
ax = 2x + 5 + c
ax - 2x = 2x - 2x + 5 + c

ax - 2x = c + 5
X(a - 2) = c + 5
X(a - 2)/(a - 2) = c+5/(a-2)

X = c+5/a-2

I believe this would be the solution.

8 0

3 years ago

Lexi has 514 cups of popcorn. How many friends can she share with if each person gets 78

s2008m [1.1K]

Answer:

approx. 6 friends brainiest rate 5 stars and thank mee : )

Step-by-step explanation:

3 0

1 year ago

Read 2 more answers

Please help me thank you

Hoochie [10]

Answer:

$\large\boxed{\sin2\theta=\dfrac{\sqrt3}{2},\ \cos2\theta=\dfrac{1}{2}}$

Step-by-step explanation:

We know:

$\sin2\theta=2\sin\theta\cos\theta\\\\\cos2\theta=\cos^2\theta-\sin^2\thet$

We have

$\sin\theta=\dfrac{1}{2}$

Use $\sin^2\theta+\cos^2\theta=1$

$\left(\dfrac{1}{2}\right)^2+\cos^2\theta=1\\\\\dfrac{1}{4}+\cos^2\theta=1\qquad\text{subtract}\ \dfrac{1}{4}\ \text{from both sides}\\\\\cos^2\theta=\dfrac{4}{4}-\dfrac{1}{4}\\\\\cos^2\theta=\dfrac{3}{4}\to\cos\theta=\pm\sqrt{\dfrac{3}{4}}\to\cos\theta=\pm\dfrac{\sqrt3}{\sqrt4}\to\cos\theta=\pm\dfrac{\sqrt3}{2}\\\\\theta\in[0^o,\ 90^o],\ \text{therefore all functions have positive values or equal 0.}\\\\\cos\theta=\dfrac{\sqrt3}{2}$

$\sin2\theta=2\left(\dfrac{1}{2}\right)\left(\dfrac{\sqrt3}{2}\right)=\dfrac{\sqrt3}{2}\\\\\cos2\theta=\left(\dfrac{\sqrt3}{2}\right)^2-\left(\dfrac{1}{2}\right)^2=\dfrac{3}{4}-\dfrac{1}{4}=\dfrac{3-1}{4}=\dfrac{2}{4}=\dfrac{1}{2}$

3 0

3 years ago