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Mamont248 [21]
3 years ago
5

Sherri is processing lab data on the locations of retinal activations in the brain. She notes that even though the fovea account

s for only 0.01 percent of the retina's area, signals from the fovea account for 8 to 10 percent of the retinotopic map on the cortex. This apportioning to the small fovea of a large area on the cortex is known as _____.
Chemistry
1 answer:
Mkey [24]3 years ago
5 0

Answer:

cortical magnification factor

Explanation:

The area representinf the cone-rich fovea is much larger than one would expect from the fovea's small size.  The cortical magnification factor in the human cortex has been determined using a technique called brain imaging, which makes it posible to create pictures of the brain's activity.

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The steam rotates a turbine that activates a generator, which produces electricity. Many power plants still use fossil fuels to boil water for steam. Geothermal power plants, however, use steam produced from reservoirs of hot water found a couple of miles or more below the Earth's surface.
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Small quantities of hydrogen gas can be prepared in the lab by addition of hydrochloric acid to zinc. The gas is typically colle
madam [21]

Answer:

0.214 L

Explanation:

Step 1: Write the balanced equation

This is a single displacement reaction.

Zn(s) + 2 HCl(aq) ⇒ ZnCl₂(aq) + H₂(g)

Step 2: Calculate the moles corresponding to 0.625 g of Zn

The molar mass of Zn is 65.38 g/mol.

0.625 g × 1 mol/65.38 g = 9.56 × 10⁻³ mol

Step 3: Calculate the moles of H₂ produced from 9.56 × 10⁻³ moles of Zn

The molar ratio of Zn to H₂ is 1:1. The moles of H₂ produced are 1/1 × 9.56 × 10⁻³ mol = 9.56 × 10⁻³ mol.

Step 4: Calculate the volume occupied by 9.56 × 10⁻³ moles of hydrogen

Assuming standard pressure and temperature, 1 mole of hydrogen occupies 22.4 L.

9.56 × 10⁻³ mol × 22.4 L/1 mol = 0.214 L

8 0
3 years ago
In the alkaline phosphatase assay, you will you be monitoring the formation of product by measuring the absorbance of the soluti
blondinia [14]

Answer:

a. At pH 9, the product, p-nitrophenol, will be ionized, the solution will appear yellow in color, and thus can be monitored at the wavelength of maximum absorption for the phenolate ion which is 400nm

Explanation:

In alkaline phosphatase assay, the hydrolysis of p nitrophenyl phosphate to p nitrophenol happens. When the ph is 9, the product which is p nitrophenol would undergo ionization. The solution is going to appear to be of yellow and it can be monitored at a wavelength for maximum absorption of phenolate ions at 400nm.

Option A is the answer to the question.

5 0
3 years ago
Question 7 options: The cell potential of an electrochemical cell made of an Fe, Fe2 half-cell and a Pb, Pb2 half-cell is _____
larisa [96]

Answer: Thus the cell potential of an electrochemical cell is +0.28 V

Explanation:

The calculation of cell potential is done by :

E^0=E^0_{cathode}- E^0_{anode}

Where both E^0 are standard reduction potentials.

E^0_{[Fe^{2+}/Fe]}= -0.41V

E^0_{[Pb^{2+}/Pb]}=-0.13V

As Reduction takes place easily if the standard reduction potential is higher(positive) and oxidation takes place easily if the standard reduction potential is less(more negative). Thus iron acts as anode and lead acts as cathode.

E^0=E^0_{[Pb^{2+}/Pb]}- E^0_{[Fe^{2+}/Fe]}

E^0=-0.13- (-0.41V)=0.28V

Thus the cell potential of an electrochemical cell is +0.28 V

5 0
3 years ago
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