Answer:
36 mL of water can be displace by the 408 g lead
Explanation:
Given data:
Mass of lead = 408 g
Volume of water displaced by lead = ?
Solution:
The volume of water displace by the lead would be equal to the given volume of lead.
So we will calculate the volume from given mass of lead from density formula.
Density:
Density is equal to the mass of substance divided by its volume.
Units:
SI unit of density is Kg/m3.
Other units are given below,
g/cm3, g/mL , kg/L
Formula:
D=m/v
D= density
m=mass
V=volume
Density of lead is 11.36 g/cm³.
d = m/v
11.36 g/cm³ = 408 g/ v
v = 408 g/ 11.36 g/cm³
v =36 cm³
1 cm³ = 1 mL
volume = 36 mL
36 mL of water can be displace by the 408 g lead.
Answer:
The volume will be 2600 L.
Explanation:
Initial temperature (
) = 25°C = (25 + 273) K = 298K
Final temperature (
) = 54°C = (54 + 273) K = 327 K
By using the combined gas law equation,
= 
or, 
= 
or, 3060 × 327 = 380 × 
or, ≈ 2600 L
Hence the volume of the balloon will be about 2600 L.
Machines that are fairly simple and make working easier
Ammonium iodide, or NH₄I, is a salt. Since all salts are strong electrolytes, when ammonium iodide is dissolved in water, it would dissociate into ammonium ions and iodide ions. Hence, the major species present would be: <em>NH₄⁺ and I⁻ ions</em>.
