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JulsSmile [24]
4 years ago
5

821x54 using an area model

Mathematics
1 answer:
Nookie1986 [14]4 years ago
8 0
44334 is the number
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What is the sum of5 + 4 +
Nadusha1986 [10]

Answer:

9

Step-by-step explanation:

5+4=9

6 0
3 years ago
Read 2 more answers
Richard and Teo have a combined age of 37. Richard is 4 years older than twice​ Teo's age. How old are Richard and​ Teo?
valkas [14]

Answer:

Teo is 11 years old and Richard is 26 years old.

Step-by-step explanation:

Let R be the age of Richard and T be the age of Teo.

<u><em>First set up the equations:</em></u>

The combined age of Teo and Richard is 37:

R+T=37

Richard is four years old than twice Teo's age:

R=2T+4

<u><em>Then, solve the equations:</em></u>

Substitute (2) to (1) and solve for T:

(2T+4)+T=37

3T=11

T=11

Solve for R using (2):

R=2(11)+4

R=22+4

R=26

5 0
3 years ago
Megan has been planting young trees in her garden. One maple tree is 66 centimeters tall and is growing 8 centimeters per month.
EastWind [94]
Once per month there is food that is 33 centimeters long
7 0
2 years ago
What is the SLOPE of the LINES that passes through the points (13,1) and (-2,4 )
olga55 [171]

Answer: M= slope

M= -1/5

Step-by-step explanation:

M= the change in y over the change in x so you would do 1-4 over 13-(-2) which gives you -3 over 15 which is simplified to give you the answer which is -1/5.

7 0
3 years ago
Exhibit 6-5 The weight of items produced by a machine is normally distributed with a mean of 8 ounces and a standard deviation o
hjlf

Answer:

46.18% of the items will weigh between 6.4 and 8.9 ounces.

Step-by-step explanation:

We are given that the weight of items produced by a machine is normally distributed with a mean of 8 ounces and a standard deviation of 2 ounces.

<em>Let X =  weight of items produced by a machine</em>

The z-score probability distribution for is given by;

                Z = \frac{  X -\mu}{\sigma}  ~ N(0,1)

where, \mu = mean weight = 8 ounces

            \sigma = standard deviation = 2 ounces

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

So, percentage of items that will weigh between 6.4 and 8.9 ounces is given by = P(6.4 < X < 8.9) = P(X < 8.9 ounces) - P(X \leq 6.4 ounces)

   P(X < 8.9) = P( \frac{  X -\mu}{\sigma} < \frac{  8.9-8}{2} ) = P(Z < 0.45) = 0.67364  {using z table}

   P(X \leq 70) = P( \frac{  X -\mu}{\sigma} \leq \frac{  6.4-8}{2} ) = P(Z \leq -0.80) = 1 - P(Z < 0.80)

                                                 = 1 - 0.78814 = 0.21186

<em>Now, in the z table the P(Z </em>\leq<em> x) or P(Z < x) is given. So, the above probability is calculated by looking at the value of x = 0.45 and x = 0.80 in the z table which has an area of </em>0.67364<em> and </em>0.78814<em> respectively.</em>

Therefore, P(6.4 < X < 8.9) = 0.67364 - 0.21186 = 0.4618 or 46.18%

<em>Hence, 46.18% of the items will weigh between 6.4 and 8.9 ounces.</em>

8 0
4 years ago
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