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Vladimir [108]
3 years ago
8

Someone help me with this ASAP!!

Mathematics
2 answers:
deff fn [24]3 years ago
7 0
Part 3 is going to be 3.5
omeli [17]3 years ago
6 0

thats all right but part 3 of 3 is 7.5

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If VT=2,what is the length of PT?
marusya05 [52]

Step-by-step explanation:

\underline{ \underline{ \text{Given : }}}

  • Perpendicular ( P ) = VT = 2
  • Base ( b ) = PT
  • \theta =  \tt{60 \degree}

\underline{ \underline{ \text{Solution}}} :

\tt{ \tan(60 \degree)  =  \frac{perpendicualar}{base}}

⟶ \tt{ \sqrt{3}  =  \frac{2}{PT}}

⟶ \tt{ \sqrt{3}  \: PT= 2}

⟶ \tt{PT =  \frac{2}{ \sqrt{3}} }

⟶ \tt{PT= \boxed{\tt{ \frac{2 \sqrt{3} }{{3} }}}}

Hope I helped ! ♡

Have a wonderful day / night ! ツ

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6 0
3 years ago
So i need some help about percentages.
Lisa [10]
The answer is 12. if you need help, do 60•.2
7 0
3 years ago
Read 2 more answers
Kyle and Jorge play for a major league baseball team.
9966 [12]
Answer:
15
Explanation
4 0
3 years ago
Simplify (x2y)3. need this asap
bogdanovich [222]

Answer:

3x^2y

Step-by-step explanation:

hope this helps : )

4 0
3 years ago
Consider independent simple random samples that are taken to test the difference between the means of two populations. The varia
Arturiano [62]

Answer:

d. t distribution with df = 80

Step-by-step explanation:

Assuming this problem:

Consider independent simple random samples that are taken to test the difference between the means of two populations. The variances of the populations are unknown, but are assumed to be equal. The sample sizes of each population are n1 = 37 and n2 = 45. The appropriate distribution to use is the:

a. t distribution with df = 82.

b. t distribution with df = 81.

c. t distribution with df = 41.

d. t distribution with df = 80

Solution to the problem

When we have two independent samples from two normal distributions with equal variances we are assuming that  

\sigma^2_1 =\sigma^2_2 =\sigma^2

And the statistic is given by this formula:

t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{S_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}}}

Where t follows a t distribution with n_1+n_2 -2 degrees of freedom and the pooled variance S^2_p is given by this formula:

\S^2_p =\frac{(n_1-1)S^2_1 +(n_2 -1)S^2_2}{n_1 +n_2 -2}

This last one is an unbiased estimator of the common variance \sigma^2

So on this case the degrees of freedom are given by:

df= 37+45-2=80

And the best answer is:

d. t distribution with df = 80

5 0
3 years ago
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