The graph of the linear function k passes through points (-7,0) and ((1,8)
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Answer:
The given equation is
⇒y≥
As domain of the function is 3 x-2≠0
x≠2/3
⇒For different values of x we get different values of y.
When, x>2/3 , we get positive values of y.
So , y≥ 0
and when x< 2/3 , we get values of y which are negative.
i.e y≤0
At x=2/3, function is not defined.So at that point there does not exist any value of y.
