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sdas [7]
3 years ago
14

What is the value of f(0)

Mathematics
1 answer:
DIA [1.3K]3 years ago
7 0
The answer is zero because any number multiplied by 0 is 0 (the multiplicative property of zero)

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Imagine your friend uses long division to determine the quotients, and is confused by how quickly you
Natalija [7]

Answer:

I usually think about the dividend and divisor

Step-by-step explanation:

and what are the possible numbers to divide it easily

hope it helps

5 0
3 years ago
Read 2 more answers
How many 0.4 liter glasses of water are contained in a 5.2 - liter pitcher? How do you find it out step by step?
Novay_Z [31]
Let's start out with what we do know:
We have a 5.2L pitcher and 0.4L glasses and we want to know how many glasses we can fill with the 5.2L pitcher of water.

To answer that, we need to divide 5.2L by 0.4L in order to get the number of glasses (the number of 0.4L glasses that can go into a 5.2L pitcher)

So our equation will look like this:

n = \frac{5.2L}{0.4L} where n = number of glasses
so by doing that division we get:

n = 13
Notice that the L's cancel out leaving us with a plain number.

So a 5.2L pitcher of water can fill up 13 glasses!
7 0
3 years ago
Factor the expression –5g + 15h – 25.
shtirl [24]

Answer:

-5(g-3h+5)

Step-by-step explanation:

-5g+15h-25

-5(g-3h+5)

3 0
2 years ago
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PLEASE I NEED HELP WITH THIS!!!!​
trapecia [35]

Answer:

oh yeah thats the 3rd one

Step-by-step explanation:

8 0
3 years ago
2<br>If A=<br>4 3<br>find A1 using<br>elementary row operations.​
MA_775_DIABLO [31]

Answer:   A^{-1}=\left[\begin{array}{cc}\frac{3}{2}&-\frac{1}{2}\\-2&1\end{array}\right]

<u>Step-by-step explanation:</u>

                  \left[\begin{array}{cc}2&1\\4&3\end{array}\right]=\left[\begin{array}{cc}1&0\\0&1\end{array}\right]

\dfrac{1}{2}Row\ 1\rightarrow\left[\begin{array}{cc}1&\frac{1}{2}\\4&3\end{array}\right]=\left[\begin{array}{cc}\frac{1}{2}&0\\0&1\end{array}\right]

Row\ 2 -4 \ Row\ 1\rightarrow \left[\begin{array}{cc}1&\frac{1}{2}\\0&1\end{array}\right]=\left[\begin{array}{cc}\frac{1}{2}&0\\-2&1\end{array}\right]

Row\ 1-\dfrac{1}{2}\ Row\ 2 \rightarrow \left[\begin{array}{cc}1&0\\0&1\end{array}\right]=\left[\begin{array}{cc}\frac{3}{2}&-\frac{1}{2}\\-2&1\end{array}\right]

5 0
3 years ago
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