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GarryVolchara [31]
3 years ago
14

The total employment for police officers in 2006 was 648,000. If there are 719,000 police officers in 2016, what will the percen

t increase have been?
Mathematics
2 answers:
elixir [45]3 years ago
7 0

Answer:  10.96%.

Step-by-step explanation:

The percent increase is given by :-

\dfrac{\text{Increase in amount}}{\text{Previous amount}}\times 100

Given : The total employment for police officers in 2006 was 648,000.

If there are 719,000 police officers in 2016, then increases in police officers = 719000-648000=71000

The percent increase will be :_

\dfrac{71000}{648000}\times 100=10.9567901235\approx10.96\%

Hence, the percent increase = 10.96%.

Dmitriy789 [7]3 years ago
4 0

\frac{719000 - 648000}{648000} \times 100\% \\  = 11.0\%(corr \: to \: 3 \: sig. \: fig.)
The percentage increase is 11%
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