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il63 [147K]
2 years ago
8

Cannn. Somebodddy answerrr them all, pleaseee

Mathematics
1 answer:
pentagon [3]2 years ago
7 0

Answer:

Hi

Step-by-step explanation:

You might be interested in
A solid gold ingot has a volume of 200 cm3 and a mass of 3.9 kg.
Contact [7]

Step-by-step explanation:

convert 3.9 kg to grams

3.9×1000=3900 g

density = mass/ volume

= 3900/ 200

=19.5 g/cm3

7 0
2 years ago
An inspector checks 98 cell phones and finds that 2 of them are defective. A company has 850 of these phones. How many of the co
jekas [21]

Answer:

17

Step-by-step explanation:

As 2 phones are defective from a group of 98 that were checked, you can determine a percentage:

2/98= 2%

This indicates that 2% of the phones are likely to be defective and because of that you can find 2% of 850:

850*2%= 17

According to this, 17 phones are likely to be defective.

3 0
3 years ago
19. The product of two consecutive integers is 5 more than three times the larger
dusya [7]
X = larger number
x-1 = smaller number

x*(x-1)=5+3x

x^2-4x-5=0 use the formula

x=5
x-1=4
the 2 numbers are 5&4 or -1,-2


6 0
2 years ago
15. Alex bought a 711 foot tree. When he got it home, he cut 1
kolbaska11 [484]

Answer:

this other dudes answer don’t make any sense

4 0
3 years ago
Tensile-strength tests were carried out on two different grades of wire rod (Fluidized Bed Patenting of Wire Rods, Wire J., June
Shtirlitz [24]

Answer:

t=\frac{(123.6-107.6)-(10)}{\sqrt{\frac{2^2}{129}+\frac{1.3^2}{129}}}=28.569

p_v =P(t_{256}>28.569) \approx 0

So with the p value obtained and using the significance level given \alpha=0.1 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the true average strength for the 1078 grade exceeds that for the 1064 grade by more than 10 kg/mm2.

Step-by-step explanation:

The statistic is given by this formula:

t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{\sqrt{\frac{s^2_1}{n_1}+\frac{s^2_2}{n_2}}}

Where t follows a t distribution with n_1+n_2 -2 degrees of freedom

The system of hypothesis on this case are:

Null hypothesis: \mu_1 \leq \mu_2 +10

Alternative hypothesis: \mu_1 >\mu_2 +10

Or equivalently:

Null hypothesis: \mu_1 - \mu_2 \leq 10

Alternative hypothesis: \mu_1 -\mu_2>10

Our notation on this case :

n_1 =129 represent the sample size for group AISI 1078

n_2 =129 represent the sample size for group AISI 1064

\bar X_1 =123.6 represent the sample mean for the group AISI 1078

\bar X_2 =107.6 represent the sample mean for the group AISI 1064

s_1=2.0 represent the sample standard deviation for group 1 AISI 1078

s_2=1.3 represent the sample standard deviation for group AISI 1064

And now we can calculate the statistic:

t=\frac{(123.6-107.6)-(10)}{\sqrt{\frac{2^2}{129}+\frac{1.3^2}{129}}}=28.569

Now we can calculate the degrees of freedom given by:

df=129+129-2=256

And now we can calculate the p value using the altenative hypothesis:

p_v =P(t_{256}>28.569) \approx 0

So with the p value obtained and using the significance level given \alpha=0.1 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the true average strength for the 1078 grade exceeds that for the 1064 grade by more than 10 kg/mm2.  

7 0
3 years ago
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