Step-by-step explanation:
1. k = 76°
2. r = 25cm
3. as the drawing attached
one pair of parallel lines : AB and DC
one pair of equal angles : <em>L</em><em> </em>A and <em>L</em><em> </em>D
4. (7²× 3`¹)⁴×7^5 / (3² × 7^(-6))³
= (7^8 × 3`⁴)×7^5/ (3² × 7^(-6))³
= (7^13 × 3`⁴)/ (3^6 × 7^(-18))
= (7^(31) × 3^(-10))
= 7^31 / 3^10
Hello!
hint: we can rewrite your function as below:
<span>3/<span>tan<span>(<span>4x−3π</span>) = </span></span></span>3(1+tan4xtan3π)/tan4x−tan3π =
=<span>3/<span>tan<span>(<span>4x</span>) = </span></span></span>3cot<span>(<span>4x</span><span>)
</span></span>now, since the period P of cotangent function is pi, then the period of cot(4x), which is the period of our original function, is such that:
<span>"4P=π"
Hope this Helps! Have A Wonderful Day! :)</span>
1: always rearrange the equation to y = mx + c so....
x - y = o
x = y
So the gradient is 1 and it intersects the y axis at (0,0)
The three points could be (1,1), (2,2), (3,3) and so on
2: -x -2y = -10
Multiply everything by -1
x + 2y = 10
2y = 10 - x
y = 5 - x/2
The y intercept is 5 so you could use the point (0,5), (2,4), (4,3) and so on
3: x + y = -2
y = -2 - x
The y intercept is -2 so you could use the points (0,-2), (2,-4), (3,-5) and so on
4: -3y =-x -7
Multiply everything by -1
3y = x + 7
y = x/3 + 7/3
The y intercept is 7/3 so you could use the points (0,7/3), (3,10/3), (6,13/3) and so o
5: -y = -x + 1
y = x - 1
The y intercept is -1 so you could use the points (0,-1), (2,1), (3,2) and so on
Hope this helps! Any questions let me know :)
