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ANTONII [103]
3 years ago
12

A tennis ball, 0.314 kg, is accelerated at a rate of 164 m/s2 when hit by a professional tennis player. What force does the play

er's tennis racket exert on the ball?
Physics
1 answer:
SVEN [57.7K]3 years ago
4 0
Newton's 2nd law of motion:

                    Force = (mass) x (acceleration)

                             = (0.314 kg) x (164 m/s²)

                             =    51.5 newtons

                         (about 11.6 pounds) .

Notice that the ball is only accelerating while it's in contact with the racket.
The instant the ball loses contact with the racket, it stops accelerating, and
sails off in a straight line at whatever speed it had when it left the strings.
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1. Plot the equation y = x + 1. Use the values shown for x to determine y.
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A resistor R, inductor L, and capacitor C are connected in series to an AC source of rms voltage ΔV and variable frequency. If t
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Answer:E=\frac{\pi R\left ( \Delta V\right )^2\sqrt{LC}}{\left ( R^2+\frac{9}{4}\left (\frac{L}{C} \right )\right )}

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We know resonant frequency is given by

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The capacitance reactance is given by

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inductive reactance is given by

X_L=\omega L=\left ( \frac{2}{\sqrt{LC}}\right )L=2\sqrt{\frac{L}{C}}

Thus impedance is

Z=\left ( R^2+\left (X_L-X_C \right )^2 \right )^\frac{1}{2}

Z=\left ( R^2+\left (2\sqrt{\frac{L}{C}}-\frac{1}{2}\sqrt{\frac{L}{C}} \right )^2 \right )^\frac{1}{2}

Z=\left ( R^2+\frac{9}{4}\left ( \frac{L}{C} \right ) \right )^\frac{1}{2}

The average power delivered is

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Energy Delivered in one cycle is given by

E=P_{avg}T

E=\frac{\left (\Delta V \right )^2R}{\left ( R^2+\frac{9}{4}\left (\frac{L}{C} \right )\right )}\left ( \frac{2\pi }{\frac{2}{\sqrt{LC}}}\right )

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