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NikAS [45]
3 years ago
10

Joey drives along the 110 South freeway and notices a mile marker that reads 260 miles. He drives until he reaches the 150 mile

marker. He realizes that he went too far, so gets on the 110 North to the 175 mile marker. What is Joey’s displacement from the 260 mile marker?
Physics
1 answer:
Nostrana [21]3 years ago
8 0

Answer:

85 miles .

Explanation:

Displacement along the 110 South freeway = 260 - 150  =  110 miles

Displacement along the 110 North freeway = 150 - 175   = - 25 miles

Net displacement = 110 - 25 = 85 miles

So Joey's displacement from the 260 mile marker is 85 miles .

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Sammy Speedy, a 69.5 kg jogger, takes a jog along a walk path. If Sammy expends 1,750.0 J while jogging, how fast is he moving?
Kitty [74]

The speed of Sammy, given that he expends 1750 J while jogging is 7.1 m/s

<h3>Data obtained from the question</h3>
  • Mass (m) = 69.5 Kg
  • Energy (E) = 1750 J
  • Speed (v) =?

<h3>How to determine the speed</h3>

The speed of Samnmy can be obtained as illustrated below:

E = ½mv²

1750 = ½ × 69.5 × v²

1750 = 34.75 × v²

Divide both side by 34.75

v² = 1750 / 34.75

Take the square root of both side

v = √(1750 / 34.75)

v = 7.1 m/s

Thus, Sammy is moving with a speed of 7.1 m/s

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5 0
2 years ago
What weighs more 500 pounds of bricks or 500 pounds of feathers.
Drupady [299]

Answer:

It's the same........

6 0
3 years ago
Read 2 more answers
A solenoid with 500 turns has a radius of 0.040 m and is 40 cm long. if this solenoid carries a current of 12 a, what is the mag
frosja888 [35]
Are there any options? I had one similar to this not to long ago

7 0
3 years ago
Someone Please Help<br> Just need answerd
Elina [12.6K]

1. The spring is storing

1/2 (240 N/m) (0.40 m)² = 19.2 J ≈ 19 J

of potential energy.

2. When the spring is compressed by 0.30 m, it is storing

1/2 (240 N/m) (0.30 m)² = 10.8 J

so there was a loss of 19.2 J - 10.8 J = 8.4 J.

3. The spring is storing

1/2 (150 N/m) (0.80 m)² = 48 J

of potential energy.

4. Stretching the spring by 0.20 m more has it storing

1/2 (150 N/m) (1.0 m)² = 75 J

so that the extra weight adds 75 J - 48 J = 27 J of energy.

5 0
3 years ago
What is the maximum wavelength of incident light for which photoelectrons will be released from gallium
guajiro [1.7K]

Answer:

<em>292 nm</em>

Explanation:

The work function of gallium ∅ = 94.25 eV = 6.81 x 10^-19 J

at maximum wavelength, the energy of the photons is equal to its work function

Energy of the electron = hf

but hf = hc/λ

where h is the planck's constant = 6.63 × 10-34 m^2 kg/s

c is the speed of light = 3 x 10^8 m/s

λ is the wavelength that this occurs, which is the maximum wavelength

Equating, we have

hc/λ =  ∅

substituting, we have

(6.63 × 10-34 x 3 x 10^8)/λ = 6.81 x 10^-19

(1.989 x 10^-25)/(6.81 x 10^-19) = λ

λ = 292.07 x 10^-9 = <em>292 nm</em>

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