The speed of Sammy, given that he expends 1750 J while jogging is 7.1 m/s
<h3>Data obtained from the question</h3>
- Mass (m) = 69.5 Kg
- Energy (E) = 1750 J
- Speed (v) =?
<h3>How to determine the speed</h3>
The speed of Samnmy can be obtained as illustrated below:
E = ½mv²
1750 = ½ × 69.5 × v²
1750 = 34.75 × v²
Divide both side by 34.75
v² = 1750 / 34.75
Take the square root of both side
v = √(1750 / 34.75)
v = 7.1 m/s
Thus, Sammy is moving with a speed of 7.1 m/s
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Are there any options? I had one similar to this not to long ago
1. The spring is storing
1/2 (240 N/m) (0.40 m)² = 19.2 J ≈ 19 J
of potential energy.
2. When the spring is compressed by 0.30 m, it is storing
1/2 (240 N/m) (0.30 m)² = 10.8 J
so there was a loss of 19.2 J - 10.8 J = 8.4 J.
3. The spring is storing
1/2 (150 N/m) (0.80 m)² = 48 J
of potential energy.
4. Stretching the spring by 0.20 m more has it storing
1/2 (150 N/m) (1.0 m)² = 75 J
so that the extra weight adds 75 J - 48 J = 27 J of energy.
Answer:
<em>292 nm</em>
Explanation:
The work function of gallium ∅ = 94.25 eV = 6.81 x 10^-19 J
at maximum wavelength, the energy of the photons is equal to its work function
Energy of the electron = hf
but hf = hc/λ
where h is the planck's constant = 6.63 × 10-34 m^2 kg/s
c is the speed of light = 3 x 10^8 m/s
λ is the wavelength that this occurs, which is the maximum wavelength
Equating, we have
hc/λ = ∅
substituting, we have
(6.63 × 10-34 x 3 x 10^8)/λ = 6.81 x 10^-19
(1.989 x 10^-25)/(6.81 x 10^-19) = λ
λ = 292.07 x 10^-9 = <em>292 nm</em>