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lisabon 2012 [21]
3 years ago
5

Punnett squares are convenient ways to represent the types and frequencies of gametes and progeny in experimental crosses. this

punnett square shows the results of a yy x yy cross to form f2 progeny. use your understanding of mendel's law of segregation and the rules of probability to complete the punnett square for this cross.
Physics
1 answer:
frosja888 [35]3 years ago
3 0
First identify the gametes. Use pink labels to identify the male and female gamete types and white labels to identify the gamete frequencies.

Then identify the F2 progeny. Use pink labels to identify the progeny geno types and white labels to identify the progeny <span>frequencies.</span>
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The significant figures also known as the significant digits or precision of a number written in positional notation are digits that carry meaningful contributions to its measurements
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The highest free-standing tower in North America is the CN Tower in Toronto, Canada. From a distance of 1km from its base, the a
Whitepunk [10]
The height of the tower and the distance from its base form a right angle triangle. Thus,
tan(∅) = height / base
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4 0
3 years ago
The small ball of mass m and its supporting wire become a simple pendulum when the horizontal cord is severed. Determine the rat
natali 33 [55]

Answer:

See the attached image and the explanation below

Explanation:

We must draw a schematic of the described problem, after the sketch it is necessary to make a free body diagram, at the time before and after cutting the cord.

These free body diagrams can be seen in the attached image.

First we perform a sum of forces on the x & y axes before cutting the cord, to be able to find the T tension of the wire. (This analysis can be seen in the attached image).

In this way we get the T-wire tension equation, before cutting.

Now we make another free body diagram, for the moment when the wire is cut (see in the attached diagram).

It is important to clarify that when the cord is cut, the system will no longer be in statically, therefore newton's second law will be used for summation of forces which will be equal to the product of mass by acceleration.

Finally with equations 1 and 2 we can find the K ratio.

5 0
3 years ago
An electron with velocity v = 1.0 ´ 106 m/s is sent between the plates of a capacitor where the electric field is E = 500 V/m. I
oksano4ka [1.4K]

Answer:

The deviation in path is 4.39 \times 10^{-3}

Explanation:

Given:

Velocity v = 1 \times 10^{6} \frac{m}{s}

Electric field E = 500 \frac{V}{m}

Distance x = 1 \times 10^{-2} m

Mass of electron m = 9.1 \times 10^{-31} kg

Charge of electron q = 1.6 \times 10^{-19} C

Time taken to travel distance,

    t = \frac{x}{v}

    t = \frac{1 \times 10^{-2} }{1 \times 10^{6} }

    t = 10^{-8} sec

Acceleration is given by,

  F = qE

ma = qE

   a = \frac{qE}{m}

   a = \frac{1.6 \times 10^{-19} \times 500}{9.1 \times 10^{-31} }

   a = 8.77 \times 10^{13} \frac{m}{s^{2} }

For finding the distance, we use kinematics equations.

   y = vt + \frac{1}{2}  at^{2}

Where v = 0 because here initial velocity zero

   y = \frac{1}{2} at^{2}

   y = \frac{1}{2} \times  8.77 \times 10^{13 } \times (10^{-2} )^{2}

   y = 4.39 \times 10^{-3} m

Therefore, the deviation in path is 4.39 \times 10^{-3}

6 0
2 years ago
If a young protostar with a disk is rotating and shrinking. how much faster is it rotating after its size has decreased by a fac
maks197457 [2]
In this system we have the conservation of angular momentum: L₁ = L₂
We can write L = m·r²·ω

Therefore, we will have:
m₁ · r₁² · ω₁ = m₂ · r₂² · ω₂

The mass stays constant, therefore it cancels out, and we can solve for ω<span>₂:
</span>ω₂ =  (r₁/ r₂)² · ω<span>₁
     
Since we know that r</span>₁ = 4r<span>₂, we get:
</span>ω₂ =  (4)² · ω<span>₁
     = 16 </span>· ω<span>₁

Hence, the protostar will be rotating 16 </span><span>times faster.</span>
5 0
3 years ago
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