Answer:
Step-by-step explanation:
Factor all the factors making up the square root.
108: 2*2*3*3*3
a^7: a*a*a*a*a*a*a
b^5:b * b * b * b * b
The rule for taking a square root of this is
For every pair, you get to take one number outside the root sign and throw the other one away.
2*3*a * a * a* b * b√(3*a * b)
6a^3b^2 * √(3*a*b)
Since we don't have a figure we'll assume one of them is right and we're just being asked to check if they're the same number. I like writing polar coordinates with a P in front to remind me.
It's surely false if that's really a 3π/7; I'll guess that's a typo that's really 3π/4.
P(6√2, 7π/4) = ( 6√2 cos 7π/4, 6√2 sin 7π/4 )
P(-6√2, 3π/4) = ( -6√2 cos 3π/4, -6√2 sin 3π/4 )
That's true since when we add pi to an angle it negates both the sine and the cosine,
cos(7π/4) = cos(π + 3π/4) = -cos(3π/4)
sin(7π/4) = sin(π + 3π/4) = -sin(3π/4)
Answer: TRUE
Answer: 7
Step-by-step explanation: I had this question before
1. v=0
2. No solution
3. m=0
4. No solution
5. p= -7
6. x=5
7. -12 = - 12
8. x=5
9. 3=3
10. -32= -32
11. x=0
12. No solution
I'm sorry if anything is wrong.
