g(x) = $\frac{3}{4} f(x)$ or g(x) is 3/4 times of f(x) , F(x) and g(x) have common solution or intersecting point in the graph parabola at x=0 i.e. in origin and x = $\frac {4}{3}$ .

<u>Step-by-step explanation:</u>

We have a function f(x) = $x^{2}$ and another function , g(x) = $\frac{3}{4} x^{2}$ . In the graph of y = $x^{2}$ , the point (0, 0) is called the vertex. The vertex is the minimum point in a parabola that opens upward. In a parabola that opens downward, the vertex is the maximum point.

Graphing y = (x - h)2 + k , where h = 0 & k = 0

Function g(x) can be formed with compression in function f(x) by a factor of 3/4 , i.e. g(x) = $\frac{3}{4} f(x)$ or g(x) is 3/4 times of f(x).Domain and range of f(x) and g(x) are same ! Although structure of both functions is same the only difference is g(x) is compressed vertically by a factor 3/4. Both are graph of a parabola with vertex at (0,0). Also, F(x) and g(x) have common solution or intersecting point at x=0 i.e. in origin.

7 0

3 years ago

A train leaves Kaduna for Lagos at 64km/h and an express to Kaduna leaves Lagos an hour later at 96km/h. If the distance between

LenKa [72]

Good to see you here. Now back to the train.

Kaduna, K Lagos, L

Train leaves at 64 km/h

One hour late second train leaves Lagos at 96 km/h.

At the point they meet, if first train has been travelling for "x" hours. Second train has been travelling for (x-1) hour.

At the point the meet, the total distance travelled is equal to 624 km.

Therefore:

64(x) + 96(x-1) = 624
64x + 96x - 96 = 624
160x = 624+96
160x = 720 , x = 720/160 = 4.5

So when they meet, the first train which left Kaduna has travelled= 64x = 64*4.5= 288km from Kaduna.

So it is (624-288) km from Lagos. = 336 Km from Lagos.

Second train which left Lagos has travelled = 96(x-1) = 96(4.5-1) = 336km.
The second train is also 336 km away from Lagos.

Cheers.

3 0

3 years ago