Let's take the derivative of each term one by 1
x^2
Apply the power rule for derivatives.
2x^(2-1) = 2x
You get 2x.
2x
Apply the power rule (x^1) and the constant multiple rule.
2 * x^(1-1) = 2 * x^0 = 2
You get 2.
-4
The derivative of a constant is 0.
Put that together and you get 2x + 2
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Answer:
3
Step-by-step explanation:
note that zeros and x-intercepts are the same with different names
There are 2 zeros from the quadratic factor and 1 from the linear factor.
To find them equate the function to zero, that is
(x² - x - 2)(3x - 2) = 0
(x - 2)(x + 1)(3x-2) = 0 ← factoring the quadratic
equate each factor to zero and solve for x
x - 2 = 0 ⇒ x = 2
x + 1 = 0 ⇒ x = - 1
3x - 2 = 0 ⇒ x = 
Answer:
1035272
Step-by-step explanation:
Answer:
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