3 years ago

Find −3a2 − b3 + 3c2 − 2b3 if a = 2, b = −1, and c = 3.

1 answer:

3 0

A = 2, B = -1, C = 3

-3a^2 - b^3 + 3c^2 - 2b^3
-3(2^2) - (-1^3) + 3(3^2) - 2(-1^3)
-3(4) - (-1) + 3(9) - 2(-1)
-12 + 1 + 27 + 2
-12 + 30
《18 <span>》</span>

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