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ivolga24 [154]
3 years ago
15

Which describes the cross section of a square prism that passes through vertices A, B, and C?

Mathematics
2 answers:
expeople1 [14]3 years ago
6 0

Answer:

In triangle ABC one side equal 8\sqrt{2} and two sides equal 4\sqrt{13}

Step-by-step explanation:

We are given a prism whose base is square with sides 8 in and height 12 in.

If we take cross section through vertices A, B and C

We will get a cross section as triangle.

In triangle ABC, sides are AB, BC and AC

AB is diagonal of top square whose side 8 in.

AB=\sqrt{8^2+8^2}=8\sqrt{2}

AC is face diagonal of front face.

AC=\sqrt{8^2+12^2}=4\sqrt{13}

BC is face diagonal of right face.

BC=\sqrt{8^2+12^2}=4\sqrt{13}

AC=BC≠AB

Hence, In triangle ABC one side equal 8\sqrt{2} and two side equal 4\sqrt{13}

CaHeK987 [17]3 years ago
3 0

Answer:

A) A recangle that is not a square

Step-by-step explanation:

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Find the value of x<br> X+8 =5x-4
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I'm pretty sure the value of it is 3

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1) function  2) not a function

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the second one is not a function because the coordinates cannot have different inputs but different outputs. each input must have only one output.

the coordinates for the second one are:

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5 0
3 years ago
Maria y juan deben realizar el mapamundi en medio pliego de cartulina para la tarea de sociales pero cada uno tiene un cuarto de
kondor19780726 [428]

Answer:

Cuando María afirma que si unen sus dos cuartos de cartulina obtendrán el medio pliego que necesitan, esto es:

  • <u>Verdadero</u>.

Step-by-step explanation:

Para entender mejor el ejercicio vamos a utilizar números cada vez que se habla de cantidades de cartulina, por lo tanto, María y Juan tienen 1/4 de cartulina cada uno, es decir, 1/4 * 2, y necesitan 1/2 pliego para poder realizar su tarea, por lo tanto, con la afirmación de María sobre unir los dos cuartos de cartulina, en caso de que sea verdadero, ocurrirá que la suma de los dos cuartos dará el medio pliego, como se muestra a continuación:

  • Total de cartulina de María y Juan = \frac{1}{4}+\frac{1}{4}
  • Total de cartulina de María y Juan = \frac{4+4}{16}
  • Total de cartulina de María y Juan = \frac{8}{16}

Procedemos a simplificar el fraccionario obtenido, sacando mitad tanto en el numerador como en el denominador:

  • Total de cartulina de María y Juan = \frac{4}{8}
  • Total de cartulina de María y Juan = \frac{2}{4}
  • <u><em>Total de cartulina de María y Juan = </em></u>\frac{1}{2}<u><em /></u>

Como puedes ver al final, <u>la cantidad de cartulina de ambos, al ser sumada, da como resultado el 1/2 (medio) pliego que necesitan para su tarea de sociales, por lo cual la afirmación de María es correcta</u>.

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