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3 years ago

Select the person responsible for the following: cotton gin

Chemistry

2 answers:

Stells [14]3 years ago

7 0

The inventor of the cotton gin in Eli Whitney

yarga [219]3 years ago

7 0

Eli Whitney... if my sources are correct.

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Why is particle physics related to the model of the universe

Nataly_w [17]

Physics beyond the Standard Model (BSM) refers to the theoretical developments needed to ... Yet, the Standard Model does not supply any fundamental particles that are good dark matter candidates. .... compared to their mass—while formation of structures similar to the galaxies in our universerequires cold dark matter.

5 0

4 years ago

The equilibrium constant, Kc, for the reaction N2O4(g)⇌2NO2(g) is 5.0×10−3. If the equilibrium mixture contains [NO2] = 0.050 M

Sergeu [11.5K]

Answer:

0.50 M is the molar concentration of $N_2O_4$ .

Explanation:

The equilibrium constant of the reaction = $K_c=5.0\times 10^{-3}$

$N_2O_4(g)\rightleftharpoons 2NO_2(g)$

Equilibrium concentration of $NO_2$ = 0.050 M

$[NO_2]=0.050 M$

Equilibrium concentration of $N_2O_4$ = ?

$[N_2O_4]= x$

The equilibrium constant of the reaction is given aSL:

$K_c=\frac{[NO_2]^2}{[N_2O_4]}$

$K_c=\frac{(0.050 M)^2}{x}=5.0\times 10^{-3}$

$x = 0.50 M$

0.50 M is the molar concentration of $N_2O_4$ .

4 0

4 years ago

a container holds 6.4 moles of gas. hydrogen gas makes up 25% of the total moles in the container. if the total pressure is 1.24

Mekhanik [1.2K]

The total pressure of the mixture of gases is equal to the sum of the pressure of each gas as if it is alone in the container. The partial pressure of a component of the mixture is said to be equal to the product of the total pressure and the mole fraction of the component in the mixture.

Partial pressure of hydrogen gas = 1.24 atm x .25 = 0.31 atm
Partial pressure of the remaining = 1.24 atm x (1-.25) = 0.93 atm

5 0

3 years ago

Read 2 more answers

Suppose that CO2 in the atmosphere was held at a constant, natural level for a few thousand years. Then, CO2 was added to double

jasenka [17]

Answer: Temperature before the increase in $CO_2$ was a few degrees lower than temperature after the increase.

Explanation:

According to Charle's Law which states that The volume of gas is directly proportional to the temperature of the gas, when pressure is kept constant.

$(Volume)\propto (Temperature)$

$\frac{volume}{temperature}=constant$ (At constant Pressure)

With the increase in level $CO_2$ in atmosphere the increase in temperature of the atmosphere will be observed.

Hence, temperature before the increase in $CO_2$ was a few degrees lower than temperature after the increase.

7 0

3 years ago

The equation for photon energy, E, is E=hc/λ

Leni [432]

Answer:

The wavelength, λ, of a photon that has an energy of E = 3.92×10⁻¹⁹ J is 5.054*10⁻⁷ m

Explanation:

The wavelength is defined for every periodic wave, that is, for the type of wave that repeats itself with exactly the same shape every given interval of time. It is the distance between two points from which the wave repeats.

Radiation is the emission, propagation and transfer of energy in any medium in the form of electromagnetic waves or particles.

The energy carried by electromagnetic radiation travels by waves. This energy is transmitted grouped in small "quanta" of energy called photons. The energy of a photon is measured in Joules (J) and is

$E=\frac{h*c}{wavelength}$

Being:

E=3.92×10⁻¹⁹ J
h= 6.626×10⁻³⁴ J⋅s (Planck's constant)
c = 2.99×10⁸ m/s (the speed of light)
wavelength=?

and replacing:

$3.92*10^{-19}J =\frac{6.626*10^{-34}J.s*2.99*10^{8}\frac{m}{s} }{wavelength}$

you get:

$wavelength =\frac{6.626*10^{-34}J.s*2.99*10^{8}\frac{m}{s} }{3.92*10^{-19}J}$

wavelength= 5.054*10⁻⁷ m

The wavelength, λ, of a photon that has an energy of E = 3.92×10⁻¹⁹ J is 5.054*10⁻⁷ m

6 0

3 years ago