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GREYUIT [131]
3 years ago
8

How many moles of copper must react to form 0.854 mol ag

Chemistry
2 answers:
makvit [3.9K]3 years ago
8 0

How many moles of copper must react to form 0.854 mol Ag? =0.427

Anna11 [10]3 years ago
7 0
This problems involves the equation, please take a picture.
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What displays the number of atoms, nature and bond types in organic compounds​
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Structural formula

Explanation:

Various type of formulae describe an organic compound. The empirical formula only shows the ratio of atoms of each element present. The molecular formula shows the exact number of atoms of each element present.

Lastly, the structural formula shows us the arrangement of these atoms in space. It shows us the number of atoms, nature and bond types in organic compounds​.

The structural formula enables us to picture what the real molecule must look like.

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Which choice is not a property of an acid?
svlad2 [7]

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A.

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3 years ago
Chemical Equations and Reactions WS
ruslelena [56]

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1,1,1

decomposition reaction

Explanation:

The reaction equation is given as:

      _Ca(OH)₂  →   _CaO    +   _H₂O

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To balance the equation, we assign variables a, b and c, then we use a mathematical approach to solve the problem;

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7 0
2 years ago
Propane has a normal boiling point of -42.04 °C and a heat of vaporization of 24.54 kJ/mole. What is the vapor pressure of propa
Mademuasel [1]

Answer : The vapor pressure of propane at 25.0^oC is 17.73 atm.

Explanation :

The Clausius- Clapeyron equation is :

\ln (\frac{P_2}{P_1})=\frac{\Delta H_{vap}}{R}\times (\frac{1}{T_1}-\frac{1}{T_2})

where,

P_1 = vapor pressure of propane at 25.0^oC = ?

P_2 = vapor pressure of propane at normal boiling point = 1 atm

T_1 = temperature of propane = 25.0^oC=273+25.0=298.0K

T_2 = normal boiling point of propane = -42.04^oC=230.96K

\Delta H_{vap} = heat of vaporization = 24.54 kJ/mole = 24540 J/mole

R = universal constant = 8.314 J/K.mole

Now put all the given values in the above formula, we get:

\ln (\frac{1atm}{P_1})=\frac{24540J/mole}{8.314J/K.mole}\times (\frac{1}{298.0K}-\frac{1}{230.96K})

P_1=17.73atm

Hence, the vapor pressure of propane at 25.0^oC is 17.73 atm.

3 0
3 years ago
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