Answer:
THR ANSWER IS C) _ methylpropanoate
V(HNO₃) = 50.0 mL in liters = 50.0 /1000 =0.05 L
M(HNO₃) = 1.50 M
Number of moles HNO₃ :
n = M x V
n = 1.50 x 0.05
n = 0.075 moles of HNO₃
HNO₃ + NaOH = H₂O + NaNO₃
1 mole HNO₃ -------- ---1 mole NaOH
0.075 moles HNO₃ ---- ?
moles NaOH = 0.075 * 1 / 1
= 0.075 moles of NaOH
V ( NaOH ) :
M = n / V
0.81 = 0.075 / V
V = 0.075 / 0.81
V =<span> 0.0925 L or 92.5 mL </span>
<span>hope this helps!</span>
Answer:
is any thing which has mass volume and empty space
Answer:
b. 2.28 M
Explanation:
The reaction of neutralization of NaOH with H2SO4 is:
2NaOH + H2SO4 → Na2SO4 + 2H2O
<em>Where 2 moles of NaOH react per mole of H2SO4</em>
<em />
To solve the concentration of NaOH we need to find the moles of H2SO4. Using the chemical equation we can find the moles of NaOH that react and with the volume the molar concentration as follows:
<em>Moles H2SO4:</em>
45.7mL = 0.0457L * (0.500mol/L) = 0.02285 moles H2SO4
<em>Moles NaOH:</em>
0.02285 moles H2SO4 * (2moles NaOH / 1 mol H2SO4) = 0.0457moles NaOH
<em>Molarity NaOH:</em>
0.0457moles NaOH / 0.020L =
2.28M
Right option:
<h3>b. 2.28 M</h3>
Answer: 149
Explanation:
Using the ideal gas equation; PV = nRT
P= Pressure = 0.910 atm, T= Temperature = ?
V= Volume = 4.0L R = Gas constant = 0.08206 L.atm/mol/K
n = number of moles = 0.297
Making 'T' the subject of the formular, we have;
T = P V/ n R = 0.910 x 4 / 0.297 x 0.08206
= 149
