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Tom [10]
3 years ago
7

The equation for photon energy, E, is E=hc/λ

Chemistry
1 answer:
Leni [432]3 years ago
6 0

Answer:

The wavelength, λ, of a photon that has an energy of E = 3.92×10⁻¹⁹ J is 5.054*10⁻⁷ m

Explanation:

The wavelength is defined for every periodic wave, that is, for the type of wave that repeats itself with exactly the same shape every given interval of time. It is the distance between two points from which the wave repeats.

Radiation is the emission, propagation and transfer of energy in any medium in the form of electromagnetic waves or particles.

The energy carried by electromagnetic radiation travels by waves. This energy is transmitted grouped in small "quanta" of energy called photons. The energy of a photon is measured in Joules (J) and is

E=\frac{h*c}{wavelength}

Being:

  • E=3.92×10⁻¹⁹ J
  • h= 6.626×10⁻³⁴ J⋅s (Planck's constant)
  • c = 2.99×10⁸ m/s (the speed of light)
  • wavelength=?

and replacing:

3.92*10^{-19}J =\frac{6.626*10^{-34}J.s*2.99*10^{8}\frac{m}{s}   }{wavelength}

you get:

wavelength =\frac{6.626*10^{-34}J.s*2.99*10^{8}\frac{m}{s}   }{3.92*10^{-19}J}

wavelength= 5.054*10⁻⁷ m

<u><em>The wavelength, λ, of a photon that has an energy of E = 3.92×10⁻¹⁹ J is 5.054*10⁻⁷ m</em></u>

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<h3>Answer:</h3>

100 g O₂

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Reading a Periodic Table

<u>Stoichiometry</u>

  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

[RxN - Balanced]   CH₄ + 2O₂ → CO₂ + 2H₂O

[Given]   2 mol CH₄

[Solve]   x g O₂

<u>Step 2: Identify Conversions</u>

[RxN] 1 mol CH₄ → 2 mol O₂

[PT] Molar Mass of O - 16.00 g/mol

Molar Mass of O₂ - 2(16.00) = 32.00 g/mol

<u>Step 3: Stoichiometry</u>

  1. Set up conversion:                     \displaystyle 2 \ mol \ CH_4(\frac{2 \ mol \ O_2}{1 \ mol \ CH_4})(\frac{32.00 \ g \ O_2}{1 \ mol \ O_2})
  2. Multiply/Divide:                           \displaystyle 128 \ g \ O_2

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 1 sig fig.</em>

128 g O₂ ≈ 100 g O₂

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