The graph of the function f(x) = –(x + 6)(x + 2) is shown below. Which statement about the function is true? The function is inc
reasing for all real values of x where x < –4. The function is increasing for all real values of x where –6 < x < –2. The function is decreasing for all real values of x where x < –6 and where x > –2. The function is decreasing for all real values of x where x < –4.
1 answer:
From the attached graph, we see that
f(x) is increassing in (- ∞ , -4), and
f(x) is decreasing in ( -4, ∞ )
therefore
The function is increasing for all real values of x where x < –4. TRUE
<span>The function is increasing for all real values of x where –6 < x < –2. (FALSE, f(x) is positive in this range)
</span><span>The function is decreasing for all real values of x where x < –6 and where x > –2. (FALSE, f(x) is negative in this range)
</span><span>The function is decreasing for all real values of x where x < –4. (FALSE, f(x) is decreasing ∀ x>-4</span>
f(x) is increassing in (- ∞ , -4), and
f(x) is decreasing in ( -4, ∞ )
therefore
The function is increasing for all real values of x where x < –4. TRUE
<span>The function is increasing for all real values of x where –6 < x < –2. (FALSE, f(x) is positive in this range)
</span><span>The function is decreasing for all real values of x where x < –6 and where x > –2. (FALSE, f(x) is negative in this range)
</span><span>The function is decreasing for all real values of x where x < –4. (FALSE, f(x) is decreasing ∀ x>-4</span>
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Answer:
Step-by-step explanation:
We want to rewrite the following as a single logarithm:
We introduce logarithm in the first term to get:
Recall that:
We apply this property to get:
This gives: