Hey,
I could actually answer the question now, so I am going to put it here as well so the people don't have to read the comments above.
<span>Use the Pythagorean Theorem to find the hypotenuse:<span>a² + b² = c²
5² + 5² = c²
25 + 25 = c²
50 = c²
√50=√(c^2 )
7.07 = c
Answer: 7
Cheers,
Izzy</span></span>
Answer:
92 attendees had activity cards
Step-by-step explanation:
Let x be the number of students with activity cards. Then 130-x is the number without, and the total revenue is ...
7x +10(130 -x) = 1024
7x +1300 -10x = 1024 . . . . eliminate parentheses
-3x = -276 . . . . . . . . . . . . . collect terms; subtract 1300
x = 92 . . . . . . divide by 3
92 students with activity cards attended the dance.
_____
<em>Comment on the solution</em>
Often, you will see such a problem solved using two equations. For example, they might be ...
Let 'a' represent the number with an activity card; 'w' the number without. Then ...
- a+w = 130 . . . . the total number of students
- 7a +10w = 1024 . . . . the revenue from ticket sales
The problem statement asks for the value of 'a', so you want to eliminate w from these equations. You can do that using substitution. Using the first equation to write an expression for w, you have ...
w = 130-a
and making the substitution into the second equation gives ...
7a +10(130 -a) = 1024
This should look a lot like the equation we used above. There, we skipped the extra variable and went straight to the single equation we needed to solve.
Answer:
Radius = 21
Step-by-step explanation:
Volume of a sphere = 4/3 * pie * radius^3
12,348 pie = 4/3 * pie * radius ^3
12,348 = 4/3 * radius^3
(12,348 * 3)/ 4 = radius^3
9261 = radius^3
radius = ![\sqrt[3]{9261}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B9261%7D)
radius = 21
Answer:
37
Step-by-step explanation:
13 blue
24 green
