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Lena [83]
3 years ago
5

¿Que mide la solubilidad en una disolución?

Chemistry
1 answer:
Alinara [238K]3 years ago
4 0

Answer:

En lugar de utilizar las ya conocidas unidades de concentración, para la solubilidad es más común emplear la siguiente: Medimos la solubilidad como la cantidad de gramos del soluto que podemos disolver en 100 gramos de disolvente.

Explanation:

You might be interested in
Atoms of iron (fe) and sulfur (s) form iron sulfide (fes) when the iron atom donates electrons to the sulfur atom. the type of b
marysya [2.9K]

Answer:

               The type of bond formed in FeS would be <u>Polar Covalent Bond</u>.

Explanation:

Types of Bonds can be predicted by calculating the difference in electronegativity.

If, Electronegativity difference is,

               Less than 0.4 then it is Non Polar Covalent  Bond

               Between 0.4 and 1.7 then it is Polar Covalent  Bond

               Greater than 1.7 then it is Ionic  Bond

For Fe and S,

                   E.N of Sulfur           =   2.58

                   E.N of Iron              =   1.83

                                                  ________

                   E.N Difference            0.75          (Polar Covalent Bond)


4 0
3 years ago
Use your periodic table and calculator as needed for the following question.
sveticcg [70]
Hope you find this answer I need points
7 0
3 years ago
What is the identity of an ion having 46 protons, 42 electrons and 60 neutrons?
Anon25 [30]

Answer:

first u lick it then out some sliva on it then rub it and once the volcano erupts u put it back in ur mouth and blow real hard ok!

Explanation:

repeat this process till the dong bleeds!

3 0
2 years ago
3. What is the energy of a photon whose frequency is 5.2 x 1015 Hz? Use the equation: E = hxv
anzhelika [568]

Answer:

3. 3.45×10¯¹⁸ J.

4. 1.25×10¹⁵ Hz.

Explanation:

3. Determination of the energy of the photon.

Frequency (v) = 5.2×10¹⁵ Hz

Planck's constant (h) = 6.626×10¯³⁴ Js

Energy (E) =?

The energy of the photon can be obtained by using the following formula:

E = hv

E = 6.626×10¯³⁴ × 5.2×10¹⁵

E = 3.45×10¯¹⁸ J

Thus, the energy of the photon is 3.45×10¯¹⁸ J

4. Determination of the frequency of the radiation.

Wavelength (λ) = 2.4×10¯⁵ cm

Velocity (c) = 3×10⁸ m/s

Frequency (v) =?

Next, we shall convert 2.4×10¯⁵ cm to metre (m). This can be obtained as follow:

100 cm = 1 m

Therefore,

2.4×10¯⁵ cm = 2.4×10¯⁵ cm × 1 m /100 cm

2.4×10¯⁵ cm = 2.4×10¯⁷ m

Thus, 2.4×10¯⁵ cm is equivalent to 2.4×10¯⁷ m

Finally, we shall determine the frequency of the radiation by using the following formula as illustrated below:

Wavelength (λ) = 2.4×10¯⁷ m

Velocity (c) = 3×10⁸ m/s

Frequency (v) =?

v = c / λ

v = 3×10⁸ / 2.4×10¯⁷

v = 1.25×10¹⁵ Hz

Thus, the frequency of the radiation is 1.25×10¹⁵ Hz.

8 0
2 years ago
Which will dissolve faster in water one gram cube of sugar or one gram of powder sugar?
krek1111 [17]
The  powder sugar because has more contact area 
8 0
3 years ago
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