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2 years ago

¿Que mide la solubilidad en una disolución?

Chemistry

1 answer:

Alinara [238K]2 years ago

4 0

Answer:

En lugar de utilizar las ya conocidas unidades de concentración, para la solubilidad es más común emplear la siguiente: Medimos la solubilidad como la cantidad de gramos del soluto que podemos disolver en 100 gramos de disolvente.

Explanation:

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Pressure of an ideal gas ___________________, when number of particles ( moles ) of gas decreases.

atroni [7]

The answer to your question is B.

3 0

3 years ago

If we increase the temperature of a pot of boiling water, what will eventually happen to the volume of water

Natasha2012 [34]

You answer should be evaporate. I hope this helps

4 0

2 years ago

The equilibrium constant is given for two of the reactions below. Determine the value of the missing equilibrium constant. 2A(g)

monitta

Answer:

The value of the missing equilibrium constant ( of the first equation) is 1.72

Explanation:

First equation: 2A + B ↔ A2B Kc = TO BE DETERMINED

⇒ The equilibrium expression for this equation is written as: [A2B]/[A]²[B]

Second equation: A2B + B ↔ A2B2 Kc= 16.4

⇒ The equilibrium expression is written as: [A2B2]/[A2B][B]

Third equation: 2A + 2B ↔ A2B2 Kc = 28.2

⇒ The equilibrium expression is written as: [A2B2]/ [A]²[B]²

If we add the first to the second equation

2A + B + B ↔ A2B2 the equilibrium constant Kc will be X(16.4)

But the sum of these 2 equations, is the same as the third equation ( 2A + 2B ↔ A2B2) with Kc = 28.2

So this means: 28.2 = X(16.4)

or X = 28.2/16.4

X = 1.72

with X = Kc of the first equation

The value of the missing equilibrium constant ( of the first equation) is 1.72

7 0

3 years ago

D. Convert 5.05 x 10-5 ML to hL.

Hitman42 [59]

Answer:

d.5.05*10^-10hl

e.0.45dg

f.7.5*10^5nm

Explanation:

d.1ml=10^-5hl

e.1dg=100000ug

f.1m=1000000000nm

4 0

2 years ago

A compound is found to contain 30.45 % nitrogen and 69.55 % oxygen by mass. To answer the question, enter the elements in the or

butalik [34]

Answer: The molecular formula of the compound is $NO_2$

Explanation:

Converting all these percentages into mass.

We take the total mass of the compound to be 100 grams, so, the percentages given for each element becomes its mass.So, the mass of each element is equal to the percentage given.

Mass of N = 30.45 g

Mass of O = 69.55 g

Step 1 : convert given masses into moles.

Moles of N= $\frac{\text{ given mass of N}}{\text{ molar mass of N}}= \frac{30.45g}{14g/mole}=2.175moles$