Given the identity tanX=sinXcosX and the relationship between the sine and cosine of complementary angles, what is tan (90°− A)?

1 answer:

6 0

Tan (90 - A) = sin (90 - A) / cos (90 - A) = (sin 90 cos A - sin A cos 90)/(cos 90 cos A + sin 90 sin A) = cos A / sin A = 1 / (sin A / cos A) = 1/tan A

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