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Luba_88 [7]
3 years ago
8

What is 4/12 in simplest form

Mathematics
2 answers:
inysia [295]3 years ago
7 0
For this, we must take out a greatest common factor. A greatest common factor is a number that both the numerator (Top number) and denominator (Bottom number) share in multiples. By this, I mean that both 4 and 12 can be made by multiplying the number 4 a certain amount of times.

4 goes into 4, 1 time, therefore, the top number can be made into a 1

4 goes 12, 3 times, therefore, the bottom number can be made into a 3

So your answer is:
1/3

I Hope this Helps! Please Feel free to message me with questions on greatest common factors or how I got the answer!

-Sinnamin
mylen [45]3 years ago
4 0
The answer is 2/6 because both of the numbers can be divided by 2. 4/2 is 2 and 12/2 is 6
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student randomly receive 1 of 4 versions(A, B, C, D) of a math test. What is the probability that at least 3 of the 5 student te
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Answer:

1.2%

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We are given that the students receive different versions of the math namely A, B, C and D.

So, the probability that a student receives version A = \frac{1}{4}.

Thus, the probability that the student does not receive version A = 1-\frac{1}{4} = \frac{3}{4}.

So, the possibilities that at-least 3 out of 5 students receive version A are,

1) 3 receives version A and 2 does not receive version A

2) 4 receives version A and 1 does not receive version A

3) All 5 students receive version A

Then the probability that at-least 3 out of 5 students receive version A is given by,

\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{3}{4}\times \frac{3}{4}+\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{3}{4}+\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}

= (\frac{1}{4})^3\times (\frac{3}{4})^2+(\frac{1}{4})^4\times (\frac{3}{4})+(\frac{1}{4})^5

= (\frac{1}{4})^3\times (\frac{3}{4})[\frac{3}{4}+\frac{1}{4}+(\frac{1}{4})^2]

= (\frac{3}{4^4})[1+\frac{1}{16}]

= (\frac{3}{256})[\frac{17}{16}]

= 0.01171875 × 1.0625

= 0.01245

Thus, the probability that at least 3 out of 5 students receive version A is 0.0124

So, in percent the probability is 0.0124 × 100 = 1.24%

To the nearest tenth, the required probability is 1.2%.

4 0
3 years ago
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