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schepotkina [342]
3 years ago
8

In 1992, only 275 people owned cellphones in Metropolis. Each year, cell phone use has continuously grown by 82%. How many cellp

hone users were there in 2000?
Mathematics
1 answer:
yKpoI14uk [10]3 years ago
5 0
For this case we have the following equation of the potential type:
 y = A (b) ^ t
 Where,
 y: number of people with cell phones
 A: initial number of people with cell phones
 b: growth rate
 t: time
 Substituting values:
 y = 275 * (1.82) ^ t
 For the year 2000 we have t = 8.
 Substituting:
 y = 275 * (1.82) ^ 8
 y = 33105.77794
 nearest whole integer:
 y = 33105
 Answer:
 there were 33105 cellphone users in 2000
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The half life of silicone-32 is 710 years. If 30 grams is present now, how much will be present in 300 years?
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Answer:

22.38 g of silicone-32 will be present in 300 years.

Step-by-step explanation:

A radioactive half-life refers to the amount of time it takes for half of the original isotope to decay and its given by

                                           N(t)=N_0(\frac{1}{2})^{\frac{t}{t_{1/2}}

where,

N(t) = quantity of the substance remaining

N_0 = initial quantity of the substance

t = time elapsed

t_{1/2} = half life of the substance

From the information given we know:

  • The initial quantity of silicone-32 is 30 g.
  • The time elapsed is 300 years.
  • The half life of silicone-32 is 710 years.

So, to find the quantity of silicone-32 remaining we apply the above equation

N(t)=30\left(\frac{1}{2}\right)^{\frac{300}{710}}=30\left(\frac{1}{2}\right)^{\frac{30}{71}}\approx22.38 \:g

22.38 g of silicone-32 will be present in 300 years.

7 0
3 years ago
-3x^{2}-21x-54 what are the zeros? (Solutions)
Irina-Kira [14]
The only way to solve if it is equal to something
assuming that the teacher wanted you to make it equal to zero do
0=-3x^2-21x-54

remember if we can do
xy=0 then assume x and y=0

so factor

0=-3x^2-21x-54
undistribute the -3
0=-3(x^2+7x+18)
remember 0 times anything=0 so
x^2+7x+18 must equal zero
use quadratice formula which is

if you have
ax^2+bx+c=0 then
x=\frac{-b+/- \sqrt{b^{2}-4ac} }{2a}

x^2+7x+18
a=1
b=7
c=18

x=\frac{-7+/- \sqrt{7^{2}-4(1)(18)} }{2(1)}
x=\frac{-7+/- \sqrt{49-72} }{2}
x=\frac{-7+/- \sqrt{-23} }{2}
i=√-1
x=\frac{-7+/- i\sqrt{23} }{2}



the zerose would be
x=\frac{-7+ i\sqrt{23} }{2} or \frac{-7- i\sqrt{23} }{2}




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