All categories

3 years ago

Responses which are acquired after birth are called _____ responses.

Mathematics

1 answer:

hichkok12 [17]3 years ago

7 0

Answer:

Learned

Step-by-step explanation:

I luv u!

You might be interested in

A rectangular field is 50 yards wide and 100 yards long. Patrick walks diagonally across the field. How far does he walk

S_A_V [24]

Answer:

Patrick walk approximately <u>112 yards</u>.

Step-by-step explanation:

Given:

A rectangular field is 50 yards wide and 100 yards long.

Patrick walks diagonally across the field.

Now, to find the distance he walk.

Length of the field = 100 yards.

Width of the field = 50 yards.

Now, to get the diagonal distance we put formula:

$Diagonal = \sqrt{length^2+width^2}$

$Diagonal = \sqrt{100^2+50^2}$

$Diagonal = \sqrt{10000+2500}$

$Diagonal = \sqrt{12500}$

$Diagonal = 111.80$

Therefore, Patrick walk approximately 112 yards.

6 0

3 years ago

How r u so good at this

iren [92.7K]

Answer:

Step-by-step explanation:

Good at what?

4 0

3 years ago

Read 2 more answers

HELP URGENT 5 STAR RATING AND BRAILY IF HELP!

stira [4]

If you divide both the Cashew butter and the macadamia butter in half and then multiply the peanut butter by 4 you will get $25.62 (after adding the answers up)

7 0

3 years ago

Read 2 more answers

I need help to find the measures and equation pls.

siniylev [52]

Answer:

Equation: 7x + 8x = 180

x = 12

∠CBA = 84

∠CFH = 96

Step-by-step explanation:

We can see that ∠CBA = ∠CFE and ∠CBD = ∠CFH.

We know that the sums of two angles on a straight line are going to be equal to 180.

∠CBA = 7x

∠CFH = 8x

To find the value of x, we must do the following:

7x + 8x = 180

15x = 180

15x/15 = 180/15

x = 12

Now we just substitute to find the angle measures:

∠CBA = 7 · 12 = 84

∠ CFH = 8 · 12 = 96

7 0

2 years ago

If <img src="https://tex.z-dn.net/?f=%5Crm%20%5C%3A%20x%20%3D%20log_%7Ba%7D%28bc%29" id="TexFormula1" title="\rm \: x = log_{a}(

timama [110]

Use the change-of-basis identity,

$\log_x(y) = \dfrac{\ln(y)}{\ln(x)}$

to write

$xyz = \log_a(bc) \log_b(ac) \log_c(ab) = \dfrac{\ln(bc) \ln(ac) \ln(ab)}{\ln(a) \ln(b) \ln(c)}$

Use the product-to-sum identity,

$\log_x(yz) = \log_x(y) + \log_x(z)$

to write

$xyz = \dfrac{(\ln(b) + \ln(c)) (\ln(a) + \ln(c)) (\ln(a) + \ln(b))}{\ln(a) \ln(b) \ln(c)}$

Redistribute the factors on the left side as

$xyz = \dfrac{\ln(b) + \ln(c)}{\ln(b)} \times \dfrac{\ln(a) + \ln(c)}{\ln(c)} \times \dfrac{\ln(a) + \ln(b)}{\ln(a)}$

and simplify to

$xyz = \left(1 + \dfrac{\ln(c)}{\ln(b)}\right) \left(1 + \dfrac{\ln(a)}{\ln(c)}\right) \left(1 + \dfrac{\ln(b)}{\ln(a)}\right)$

Now expand the right side:

$xyz = 1 + \dfrac{\ln(c)}{\ln(b)} + \dfrac{\ln(a)}{\ln(c)} + \dfrac{\ln(b)}{\ln(a)} \\\\ ~~~~~~~~~~~~+ \dfrac{\ln(c)\ln(a)}{\ln(b)\ln(c)} + \dfrac{\ln(c)\ln(b)}{\ln(b)\ln(a)} + \dfrac{\ln(a)\ln(b)}{\ln(c)\ln(a)} \\\\ ~~~~~~~~~~~~ + \dfrac{\ln(c)\ln(a)\ln(b)}{\ln(b)\ln(c)\ln(a)}$

Simplify and rewrite using the logarithm properties mentioned earlier.

$xyz = 1 + \dfrac{\ln(c)}{\ln(b)} + \dfrac{\ln(a)}{\ln(c)} + \dfrac{\ln(b)}{\ln(a)} + \dfrac{\ln(a)}{\ln(b)} + \dfrac{\ln(c)}{\ln(a)} + \dfrac{\ln(b)}{\ln(c)} + 1$

$xyz = 2 + \dfrac{\ln(c)+\ln(a)}{\ln(b)} + \dfrac{\ln(a)+\ln(b)}{\ln(c)} + \dfrac{\ln(b)+\ln(c)}{\ln(a)}$

$xyz = 2 + \dfrac{\ln(ac)}{\ln(b)} + \dfrac{\ln(ab)}{\ln(c)} + \dfrac{\ln(bc)}{\ln(a)}$

$xyz = 2 + \log_b(ac) + \log_c(ab) + \log_a(bc)$

$\implies \boxed{xyz = x + y + z + 2}$

(C)

6 0

2 years ago