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Ede4ka [16]
3 years ago
5

What is the converse of the conditional statement?

Mathematics
1 answer:
dem82 [27]3 years ago
5 0

Answer:

according to me 1st option seems to be correct❤️

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I need to find the domain and ranges of some of these graphs and I can’t really do the last few! Can anyone help?
hodyreva [135]
(1) For the parabola on the bottom row, the domain would be R and the range would be y ≥ -5

(2) For the hyperbola on the bottom row, the domain would be R\{3} (since there is an asymptote at x = 3) and the range would be R\{4} (since there is an asymptote at y = 4)

(3) For the square root function on the bottom row, the domain would be x ≥ -5 and the range would be (-∞, -2]

(4) For the function to the very right on the bottom row, the domain would be R and the range would be (-∞, -3]
3 0
3 years ago
A card is drawn at random from a standard pack of playing cards.
Hatshy [7]

Answer:

the chance at getting 9 is 17% and then 50% for the coin

Step-by-step explanation:

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2 years ago
What is the expanded form to 103,727,495
artcher [175]
100,000,000 3.000.000 700,000 20,000 7,000 400 90 5
6 0
3 years ago
Read 2 more answers
X²+y²-6x+14y-1=0<br> and please show your work so I can learn
Eva8 [605]

Hello there,

I hope you and your family are staying safe and healthy during this winter season.

x^2 + y^2 -6x+14y-1=0

We need to use the Quadratic Formula*

x =\frac{-b+\sqrt{b^2}-4ac }{2a} , \frac{-b-\sqrt{b^2} -4ac }{2a}

Thus, given the problem:

a = 1, b=-6, c=y^2+14y-1

So now we just need to plug them in the Quadratic Formula*

x=\frac{6+2\sqrt{(-6)^2-4(y^2+14y-1)} }{2} , x=\frac{6-\sqrt{(-6)^2-4(y^2+14y-1)} }{2}

As you can see, it is a mess right now. Therefore, we need to simplify it

x=\frac{6+2\sqrt{10-y^2-14y} }{2}, x = \frac{6-2\sqrt{10-y^2-14y} }{2}

Now that's get us to the final solution:

x=3+\sqrt{10-y^2-14y}, x=3-\sqrt{10-y^2-14y}

It is my pleasure to help students like you! If you have additional questions, please let me know.

Take care!

~Garebear

3 0
2 years ago
Bc has endpoints b(5 ,9) and c(-4, -3). Find the coordinates of the midpoint of bc
Alex73 [517]
We can find the midpoint of any line segment using the midpoint formula: M=(x1+x2/2,y1+y2/2). Essentially, the midpoint formula finds the average of two points. If we use B and the first point and C as the second, when we plug in our values we would have M=(5-4/2,9-5/2). This can be simplified to M=(1/2,4/2) or M=(1/2,2) which is the final answer.

<span>I hope this helps.</span>
4 0
3 years ago
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