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earnstyle [38]
3 years ago
9

Why is it important to select the right data structure for storing and manipulating sparse matrices? What are the important fact

ors to consider?
Mathematics
1 answer:
Andre45 [30]3 years ago
4 0

Answer:

Always consider the cost and the reliability of the sparse matrices.

Step-by-step explanation:

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Joseph write the number pattern below 100; 101, 96; 97; 92; 93, 88; 89; what is the next pattern?
sergij07 [2.7K]

Answer:

multiples of 8

Step-by-step explanation:

79 80. 82. 81. 83 84 85 86. 88. 87. 89 90. 92. 91. 93 94 95 96. 98. 97. 99 100 ... 101. 3. (a) Write down the first 8 multiples of 8. (b) Write down the first 8 multiples of 6. ... (d) What are the next two numbers that are multiples of both 6 and 8? 4.

5 0
3 years ago
A patrolman spends three times as many hours patrolling as she does completing paper work. If she works 36 hours per week, how m
fomenos

Answer:

27 hours

Step-by-step explanation:

Let her work "x" hours for paperwork

Since, patrolling amount of hours is THREE TIMES that,

Patrolling = 3x hours

Total Hours = 36

That is including paperhour work (x) and patrolling (3x). So we can setup an equation in x and solve for x first:

x + 3x = 36

4x = 36

x = 36/4

x = 9 hours

Amount of Hours for Patarolling = 3x hours = 3(9) = 27 hours

So, she spends 27 hours patrolling

4 0
3 years ago
3 is 12% of what number
AleksAgata [21]


3/12% = 25

<em>Therefore, 3 is 12% of 25.</em>

3 0
3 years ago
Read 2 more answers
What is the inverse operation of add 5? A. divide by 5 B. add 5 C. subtract 5 D. multiply by 5​
STatiana [176]

Answer:

so times five then add five then divide by 5 however in the end there gonna cancel each other out

Step-by-step explanation:

8 0
2 years ago
what is the distance between point (-5, -2) and point (8, -3) rounded to the nearest tenth? will appreciate all the help
Sidana [21]
\text {Distance =}  \sqrt{((Y_2-Y_1)^2+(X_2-X_1)^2}

\text {Distance =}  \sqrt{((-3-(-1))^2+(8-(-5))^2}

\text {Distance =}  \sqrt{(-1)^2+(13)^2}

\text {Distance =}  \sqrt{(1+169}

\text {Distance =}  \sqrt{170}

\text {Distance =} 13.0 \text { units}
8 0
3 years ago
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