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KatRina [158]
3 years ago
13

Basil’s Work NEEED HELP ASAP !!!!

Mathematics
1 answer:
brilliants [131]3 years ago
8 0

Answer:

A.) Baskil made a mistake finding the scale factor.

Step-by-step explanation:


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Answer:

i think 4

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815<br> divide by 9 work
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What is the equation of a sine function with an amplitude of 2 and a period of 4
antiseptic1488 [7]

Answer: C

Step-by-step explanation:

For this problem, we need to know the standard form of a sine function and the meaning of each part.

Standard form: y=asin[b(x-h)]+k

a=amplitude

b=period

h=phase shift

k=vertical replacement/shifting

Now that we know the standard form and the components, we know that we can forget about k and plug in 0 for h. This would leave us with y=asin[b(x)]. We know that the amplitude is 2, therefore, a=2. To find the period, you divide 2π by the given period. \frac{2\pi }{b} =\frac{2\pi }{4\pi } =\frac{2}{4} =\frac{1}{2}, therefore, b=1/2.

y=asin[b(x)]             [plug in a=2]

y=2sin[b(x)]             [plug in b=1/2]

y=2sin(\frac{1}{2}x)

Therefore, C is the correct answer.

7 0
3 years ago
Which of the following is a factor of 10x2 − 19x 6? 5x − 3 5x − 2 2x 1 none of the above
kati45 [8]
I believe the correct answer from the choices listed above is the fourth option. The factor of the expression given as <span>10x^2 − 19x^6 would be 1 only. None of the other choices would factor correctly the expression. Hope this answers the question. Have a nice day.</span>
7 0
3 years ago
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The formula C=5/9(F−32) can be used to convert temperature from Celsius (C) to Fahrenheit (F). The highest temperature ever reco
Softa [21]

Answer:

57 °C.

Step-by-step explanation:

The formula that is used to convert temperature from Celsius (C) to Fahrenheit (F) is given by :

C=\dfrac{5}{9}(F-32) ...(1)

If T = 134° F, we need to convert the temperature in Celsius.

Put F = 134, in equation (1)

C=\dfrac{5}{9}(134-32)\\\\=\dfrac{5}{9}\times 102\\\\=56.66^{\circ} C\\\\\text{or}\\\\T=57^{\circ} C

So, the temperature on that day is 57 °C.

7 0
2 years ago
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