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prisoha [69]
4 years ago
5

What is the rate of effusion of methane, CH₄, relative to the rate of effusion of acetylene, C₂H₂?​

Chemistry
1 answer:
just olya [345]4 years ago
6 0

Answer:

1.274.

Explanation:

  • Thomas Graham found that, at a constant  temperature and pressure the rates of effusion  of various gases are inversely proportional to  the square root of their masses.

<em>∨ ∝ 1/√M.</em>

where, ∨ is the rate of diffusion of the gas.

M is the molar mass of the gas.

<em>∨₁/∨₂ = √(M₂/M₁)</em>

∨₁ is the rate of effusion of the methane.

∨₂ is the rate of effusion of acetylene gas.

M₁ is the molar mass of methane (M₁ = 16.0 g/mol).

M₂ is the molar mass of acetylene (M₂ = 26.0 g/mol).

<em>∴ The rate of effusion of methane, CH₄, relative to the rate of effusion of acetylene, C₂H₂ = ∨₁/∨₂ = √(M₂/M₁) </em>= √(26.0 g/mol)/(16.0 g/mol) = <em>1.274.</em>

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