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3 years ago

How does the sun heat the side of the Earth facing away from it?

Chemistry

1 answer:

Evgen [1.6K]3 years ago

3 0

Answer:

The sun radiates energy in all directions.

Explanation:

Most of it dissipates into space, but the tiny fraction of the sun's energy that reaches Earth is enough to heat the planet and drive the global weather system by warming the atmosphere and oceans

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Noble gas notation for molybdenum?

GuDViN [60]

Noble gas notation for molybdenum:
[Kr] 4d^5 5s^1

4 0

2 years ago

An unknown amount of mercury (II) oxide was decomposed in the lab. Mercury metal was formed and 5.20 L of oxygen was released at

Yakvenalex [24]

Answer:

68.3g

Explanation:

1. Word equation:

mercury(II) oxide → mercury + oxygen

2. Balanced molecular equation:

2HgO → 2Hg + O₂(g)

3. Mole ratio

Write the ratio of the coefficients of the substances that are object of the problem:

$2molHgO/1molO_2$

4. Calculate the number of moles of O₂(g)

Use the equation for ideal gases:

$pV=nRT\\\\\\n=\dfrac{pV}{RT}\\\\\\n=\dfrac{0.970atm\times5.20L}{0.08206atm.L/K.mol\times 390.0K}\\\\\\n=0.1576mol$

5. Calculate the number of moles of HgO

$\dfrac{2molHgO}{1molO_2}\times 0.1576molO_2=0.315molHgO$

6. Convert to mass

mass = # moles × molar mass

molar mass of HgO: 216.591g/mol

mass = 0.315mol × 216.591g/mol = 68.3g

7 0

3 years ago

The energy that a log has is transformed when burned. How does the chemical energy of the log compare to the heat and light ener

SCORPION-xisa [38]

The amount of chemical energy is equal to the amount of heat and light energy.

This is due to the principle of conservation of energy, which states that the total energy of a system remains constant.

4 0

3 years ago

What’s the molar mass for zinc nitrate? i am failing my chemistry test right now

Vlad [161]

189.36 is the answer

7 0

2 years ago

If 50.0 g of water saturated with potassium chloride at 80.0°C is slowly evaporator to dryness, how many grams of the dry salt w

balu736 [363]

Answer:

25.0 g.

Explanation:

From the solubility curve that is shown in the attached image, the solubility of KCl per 100.0 g of water is about 50.0 g.

So, a saturated solution of KCl in 50.0 g of water will contain about 25.0 g.

Thus, the grams of the dry salt that will be recovered is 25.0 g.

5 0

3 years ago