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Anna11 [10]
3 years ago
11

How many moles of o atoms are there in 25.0 g of hno3?

Chemistry
1 answer:
Marta_Voda [28]3 years ago
5 0
HNO3 molar mass = 1 + 14 +3*16 = 63 g/mol

# of moles = mass / molar mass - 25.0 g / 63 g = 0.3968 moles

# of atoms = # of moles * Avogadro number = 0.3968 mol * 6.022 *10^23 atoms/mol = 2.39 * 10^23 atoms
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<em>where n: is the moles of the gas, R: is the gas constant, T: is the temperature, P: is the measured pressure, V: is the volume of the container, and a and b: are measured constants for a specific gas.  </em>

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So, the correct statements are the Y and Z: the non-zero volumes of the gas particles effectively decrease the amount of "empty space" between them and the molecular attractions between gas particles decrease the pressure exerted by the gas.            

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