Hydro- meaning Hydrogen.
Carbon- meaning Carbon.
Hydrogen and Carbon. Carbon atoms form the framework, and Hydrogen atoms attach to them in many different configurations.
Hope this helps!
Answer:
A liquid, at any temperature, is in equilibrium with its own steam. This means that on the surface of the liquid or solid substance, there are gaseous molecules of this substance. These molecules exert a pressure on the liquid phase, a pressure known as vapor pressure.
In chemistry, when we talk about dry basis, we talk about a state in which the presence of water in a gaseous state is denied for the calculation. So vapor pressure equals zero.
When we talk about the wet basis, the presence of water in the steam is considered for the calculation, which normally is expressed as a percentage or moisture.
In summary, for a gas mixture steam:
- For dry basis, we just have <em>component A, component B....</em>
- For wet basis, we have <em>water vapor, component A, component B...</em>
So, in wet basis we have an extra component (water).
Assuming we only have 2 components in our steam, and being X the molar fraction of eact component:
- For dry basis: Xa + Xb = 1................................. Xa = 1 - Xb
- For wet basis: Xa + Xb + Xwater = 1 .............Xa = 1 - Xwater - Xb
For dry basis the mole fraction of A it is obtained by subtracting the molar fraction of B from one. And for wet basis, we have to substract the molar fraction of B <u>AND </u>the molar fraction of water vapor. So, logically, the mole fraction Xa will be less for wet basis.
Answer:
P₂ ≅ 100 atm (1 sig. fig. based on the given value of P₁ = 90 atm)
Explanation:
Given:
P₁ = 90 atm P₂ = ?
V₁ = 18 Liters(L) L₂ = 12 Liters(L)
=> decrease volume => increase pressure
=> volume ratio that will increase 90 atm is (18L/12L)
T₁ = 272 Kelvin(K) T₂ = 274 Kelvin(K)
=> increase temperature => increase pressure
=> temperature ratio that will increase 90 atm is (274K/272K)
n₁ = moles = constant n₂ = n₁ = constant
P₂ = 90 atm x (18L/12L) x (274K/272K) = 135.9926471 atm (calculator)
By rule of sig. figs., the final answer should be rounded to an accuracy equal to the 'measured' data value having the least number of sig. figs. This means P₂ ≅ 100 atm based on the given value of P₁ = 90 atm.
Answer : The mass of calcium chloride is, 116.84 grams
Solution : Given,
Molar mass of calcium chloride, = 110.98 g/mole
Number of molecules of calcium chloride =
As we know that,
1 mole of calcium chloride contains molecules of calcium chloride
or,
1 mole of calcium chloride contains 110.98 grams of calcium chloride
Or, we can say that
As, molecules of calcium chloride present in 110.98 grams of calcium chloride
So, molecules of calcium chloride present in of calcium chloride
Therefore, the mass of calcium chloride is, 116.84 grams