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Anna11 [10]
3 years ago
11

How many moles of o atoms are there in 25.0 g of hno3?

Chemistry
1 answer:
Marta_Voda [28]3 years ago
5 0
HNO3 molar mass = 1 + 14 +3*16 = 63 g/mol

# of moles = mass / molar mass - 25.0 g / 63 g = 0.3968 moles

# of atoms = # of moles * Avogadro number = 0.3968 mol * 6.022 *10^23 atoms/mol = 2.39 * 10^23 atoms
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Explanation:

From my research, a human red blood cell contains approximately 270 million hemoglobin molecules.    

A hemoglobin molecule contains four heme groups, <em>each of which has an iron ion forming a coordination complex that carries every dioxygen molecule. </em>Therefore for each hemoglobin molecule, we will have 4 dioxygen molecules. The heme groups are responsible for the transport of every dioxygen and other diatomic gases.                    

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\frac{270 \cdot10^{6} hemoglobine molecules}{1 red blood cell} \cdot \frac{4 heme group}{1 hemoglobine molecule} \cdot \frac{1 O_{2} molecules}{1 heme group} = 1 \cdot 10^{9} O_{2} \frac{molecules}{red blood cell}

So, the correct answer is 1 billion of O₂ molecules.  

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