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Citrus2011 [14]
3 years ago
14

If 1 kg of fuel is used in the above fusion reaction (2 1H + 3 1H--> 4 2He+1 0N) , the resulting helium has a mass of 0.993 k

g. In other words, 0.007 kg of mass is converted to energy. How much energy is produced by the fusion of 1 kg of hydrogen? (Hint: Use Einstein's equation, E = mc2, where E is energy in Joules, m is mass in kilograms, and c is the speed of light, 3 x 108 m/s.)
Chemistry
1 answer:
enot [183]3 years ago
6 0
Δmc
2

For one reaction:
Mass Defect =Δm
=2(m
H
​
)−m
He
​
−m
n
​

=2(2.015)−3.017−1.009
=0.004 amu
1 amu=931.5 MeV/c
2

Hence,
E=0.004×931.5 MeV=3.724 MeV
E=3.726×1.6×10
−13
J=5.96×10
−13
J

For 1 kg of Deuterium available,
moles=
2g
1000g
​
=500
N=500N
A
​
=3.01×10
26

Energy released =
2
N
​
×5.95×10
−13
J
=8.95×10
13
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Please help me!!!!!!​
Leona [35]

The answer is B

To write the equilibrium constant for an equation, all you have to do is divide the products by the reactants. The reactants are always on the left side, and the products are always on the right side. The coefficients of the elements will be written as the exponent of that same element. However, in this equation, we do not have to write any exponents, as there are no coefficient but 1.

5 0
3 years ago
explain why elements lying on the extreme right of the periodic table as from non metals but those lying on the extreme left a s
kvasek [131]
Element at Extreme Left In Periodic Table:
                                                                   The elements of Group I-A (1) are present at extreme left of the periodic table. They are called as Alkali Metals. Alkali Metals are strong metals. These elements can easily loose their valence electron. The valence shell electronic configuration of these elements is,

                                                     ns¹

where n is principle quantum number, which shows main energy level or shell. These metals can gain Noble gas configuration (stable configuration) either by loosing one electron or by gaining seven or more electrons. As it is quite reasonable to loose one electron instead of gaining seven or more electrons so these element easily loose one electron to gain noble as configuration. The Metallic character decreases along the period from left to right. So Group II-A (2) are second most metallic elements and so on. These metals at extreme left mainly exist in solid form.

Element at Extreme Right In Periodic Table:
                                                                     Elements present at extreme right of the periodic table lacks the properties of metallic character and act as non-Metals. They have almost complete outermost shell or have the deficiency of one or two electrons. They are not as hard as metallic elements and they exist with complete octet like in Noble gases, or deficient with one electron (Halogens) or two electrons (oxygen group). These elements tend to gain or accept electron if their valence shell is deficient with required number of elements. Like the valence electronic configuration of Halogens is,

                                                   ns², np⁵

So, Halogens readily accept one electron and attain noble gas configuration. Elements at extreme left exist mainly in gas phase.
5 0
3 years ago
How many total electron will fit in the 1st energy level
nevsk [136]
2 elections will fill the first energy level
4 0
3 years ago
Read 2 more answers
Please help!!!!
stealth61 [152]

Answer:

Cells are extremely small.

Explanation:

As Mendel describes in this story, cells are so small they cannot normally be seen with the naked eye. ... The total organism remains the same throughout this process, and (usually) has a longer time on earth than any one of its cells.

3 0
3 years ago
(06.04 HC)
Ksju [112]

The mass of sodium chloride at the two parts are mathematically given as

  • m=10,688.18g
  • mass of Nacl(m)=39.15g

<h3>What is the mass of sodium chloride that can react with the same volume of fluorine gas at STP?</h3>

Generally, the equation for ideal gas is mathematically given as

PV=nRT

Where the chemical equation is

F2 + 2NaCl → Cl2 + 2NaF

Therefore

1.50x15=m/M *(1.50*0.0821)

1-50 x 15=m/58.5 *(1.50*0.0821)

m=10,688.18g

Part 2

PV=m'/MRT

1*15=m'/58.5*0.0821*273

m'=39.15g

mass of Nacl(m)=m'=39.15g

Read more about Chemical Reaction

brainly.com/question/11231920

#SPJ1

7 0
2 years ago
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