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strojnjashka [21]
3 years ago
9

Floor tile costs $11 per square yard. how much will it cost to tile a bathroom that is 90 square feet?

Mathematics
1 answer:
Genrish500 [490]3 years ago
3 0
To calculate for the equivalent price in units of per square feet, we need to convert the given units from per square yard to per square feet. We calculate as follows:

<span>$11 per square yard ( 1 yard per 3 feet )^2 = $0.14 per square feet

90 square feet (</span>$0.14 per square feet) = $12.22
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Answer:

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Step-by-step explanation:

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2 years ago
Write an equation of a line in point slope form that has a slope of -3 and passes through the point (3, -4).
Nesterboy [21]

1) Point-slope form

(y-y1)=m(x-x1)

m= - 3,

point (3,-4), so x1 = 3, y1 = - 4.

(y+4)= -3(x- 3)

2)Point-slope form

(y-y1)=m(x-x1)

m= - 3/4,

point (4,5), so x1 = 4, y1 = 5.

(y-5)= - 3/4(x-4)

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3 years ago
What is the inverse of f(x)=2^x
GuDViN [60]

Answer:

<h2>{f}^{ - 1} (x) =  \frac{ln(x)}{ln(2)}</h2>

Step-by-step explanation:

f(x)=2^x

y =  {2}^{x}

x =  {2}^{y}

{2}^{y}  = x

ln( {2}^{y} )=ln(x)

yln(2)=ln(x)

<h3>\frac{yln(2)}{ln(2)}  =  \frac{ln(x)}{ln(2)}</h3><h3>y =  \frac{ln(x)}{ln(2)}</h3><h3>{f}^{ - 1} (x) =  \frac{ln(x)}{ln(2)}</h3><h3>Hope it is helpful...</h3>
3 0
3 years ago
A cylindrical can without a top is made to contain 25 3 cm of liquid. What are the dimensions of the can that will minimize the
Basile [38]

Answer:

Therefore the radius of the can is 1.71 cm and height of the can is 2.72 cm.

Step-by-step explanation:

Given that, the volume of cylindrical can with out top is 25 cm³.

Consider the height of the can be h and radius be r.

The volume of the can is V= \pi r^2h

According to the problem,

\pi r^2 h=25

\Rightarrow h=\frac{25}{\pi r^2}

The surface area of the base of the can is = \pi r^2

The metal for the bottom will cost $2.00 per cm²

The metal cost for the base is =$(2.00× \pi r^2)

The lateral surface area of the can is = 2\pi rh

The metal for the side will cost $1.25 per cm²

The metal cost for the base is =$(1.25× 2\pi rh)

                                                 =\$2.5 \pi r h

Total cost of metal is C= 2.00 \pi r^2+2.5 \pi r h

Putting h=\frac{25}{\pi r^2}

\therefore C=2\pi r^2+2.5 \pi r \times \frac{25}{\pi r^2}

\Rightarrow C=2\pi r^2+ \frac{62.5}{ r}

Differentiating with respect to r

C'=4\pi r- \frac{62.5}{ r^2}

Again differentiating with respect to r

C''=4\pi + \frac{125}{ r^3}

To find the minimize cost, we set C'=0

4\pi r- \frac{62.5}{ r^2}=0

\Rightarrow 4\pi r=\frac{62.5}{ r^2}

\Rightarrow  r^3=\frac{62.5}{ 4\pi}

⇒r=1.71

Now,

\left C''\right|_{x=1.71}=4\pi +\frac{125}{1.71^3}>0

When r=1.71 cm, the metal cost will be minimum.

Therefore,

h=\frac{25}{\pi\times 1.71^2}

⇒h=2.72 cm

Therefore the radius of the can is 1.71 cm and height of the can is 2.72 cm.

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3 years ago
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