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Evgen [1.6K]
3 years ago
8

What is the inverse of f(x)=2^x

Mathematics
1 answer:
GuDViN [60]3 years ago
3 0

Answer:

<h2>{f}^{ - 1} (x) =  \frac{ln(x)}{ln(2)}</h2>

Step-by-step explanation:

f(x)=2^x

y =  {2}^{x}

x =  {2}^{y}

{2}^{y}  = x

ln( {2}^{y} )=ln(x)

yln(2)=ln(x)

<h3>\frac{yln(2)}{ln(2)}  =  \frac{ln(x)}{ln(2)}</h3><h3>y =  \frac{ln(x)}{ln(2)}</h3><h3>{f}^{ - 1} (x) =  \frac{ln(x)}{ln(2)}</h3><h3>Hope it is helpful...</h3>
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A random sample of 100 people was taken. Eighty of the people in the sample favored Candidate A. We are interested in determinin
riadik2000 [5.3K]

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Option b - not significantly greater than 75%.

Step-by-step explanation:

A random sample of 100 people was taken i.e. n=100

Eighty of the people in the sample favored Candidate i.e. x=80

We have used single sample proportion test,

p=\frac{x}{n}

p=\frac{80}{100}

p=0.8

Now we define hypothesis,

Null hypothesis H_0 : candidate A is significantly greater than 75%.

Alternative hypothesis H_1 : candidate A is not significantly greater than 75%.

Level of significance \alpha=0.05

Applying test statistic Z -proportion,

Z=\frac{\widehat{p}-p_0}{\sqrt{\frac{p_0(1-p_0)}{n}}}

Where, \widehat{p}=80\%=0.80 and p=75%=0.75

Substitute the values,

Z=\frac{0.80-0.75}{\sqrt{\frac{0.75(1-0.75)}{100}}}

Z=\frac{0.80-0.75}{\sqrt{\frac{0.1875}{100}}}

Z=\frac{0.05}{0.0433}

Z=1.1547

The p-value is

P(Z>1.1547)=1-P(Z

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So we fail to reject the null hypothesis and conclude that the A is not significantly greater than 75%.

Therefore, Option b is correct.

7 0
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