Answer:
Explanation:
a ) Distance of screen (D) = 50 X 10⁻²
Wavelength of light λ = 690 x 10⁻⁹
d = width of slit
Distance between first and third dark fringe = 2 x fringe width
= 2 x λD/d = 3 x 10⁻³
d = 2 x 690 x 10⁻⁹ x 50 x 10⁻² /3 x 10⁻³ = 0.23 mm
b ) Width of central bright fringe = 2 λD/d
2 x 690 x 10⁻⁹ x 50 x 10⁻² /23 x 10⁻⁵ m
= 3 mm.
Number of protons = atomic number (12)
Mass Number = 0.25
mass number = number of protons + number of neutrons
Number of neutrons = mass number - number of protons
Number of neutrons = 0.25 - 12
number of neutrons = - 11.75
Here's one easy way:
-- Hang an object from a scale. Write down its weight in air.
-- Keep the object hanging from the scale, but let it down into water,
or whatever fluid you're interested in.
-- Read the scale again. Write down its weight in the fluid.
-- Dry everything off, clean up the lab, and go to your office with your notebook.
-- In your notebook, turn to the page with that day's observations.
Notice that the object's weight in air was greater than its weight in the fluid.
-- Subtract the weight in fluid from the weight in air.
The difference is the buoyant force on the object when it's in the fluid.
Answer:
T = 243.80 N
Explanation:
In order to calculate the tension T in each of the cables, you take into account the Newton second law for the vertical component of the forces involved.
(1)
where you have used the fact that both cables have the same tension T, and they make the same angle with the horizontal.
W is the weigh of the loudspeaker and has the folowing values:
Next, you can calculate the angle θ by using the information about the length of the cables and the distance from the ceiling to the loudspeaker:
Finally, you solve the equation (1) for T, and then you replace the values of the other parameters:
The tension in each cable is 243.80N
Assuming you are asking about some sort of oscillation, the magnitude of the net force is maximum where the acceleration of the object is the largest. The velocity of an object is maximum where the acceleration is zero.