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Nadya [2.5K]
3 years ago
7

From a branch 35 m high, a 0.75 kg bird dives into a small fish tank containing

Physics
1 answer:
Bad White [126]3 years ago
7 0

Answer:

ΔT = 1.22*10^-3 °C

Explanation:

First, you calculate the potential energy of the bird when it is at 35 m high. The potential energy is also the mechanical energy of the bird in this case.

U=mgh

m: mass of the bird = 0.75kg

g: gravitational constant = 9.8m/s^2

h: height = 35m

U=(0.75kg)(9.8m/s^2)(35m)=257.25\ J

All this energy is given to the water. You use the following formula in order to calculate the change in temperature:

Q=mc\Delta T

m: mass of the water = 50kg

c: specific heat of water = 4186 J/kg°C

Q is equal to U (potential energy of the bird) because the bird gives all its energy to water. By doing ΔT the subject of the formula you obtain:

\Delta T=\frac{Q}{mc}=\frac{257.25J}{(50kg)(4186J/kg°C)}=1.22*10^{-3}\ \°C

hence, the maximum rise in temperature is 0.00122 °C

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Two positive point charges that are equal in magnitude are fixed in place, one at x = 0.00 m and the other at x = 1.00 m, on the
olga55 [171]

Answer:

0.5 m

Explanation:

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So,

\frac{KQq}{x^{2}}=\frac{KQq}{\left ( 1-x \right )^{2}}

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3 years ago
Courtney wants to practice doing science. Which example best illustrates her
dybincka [34]

Answer:

A

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because she wants to practice science and A is the practical option.

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If two different substances, with the same mass (1 gram) absorb the same amount of energy, which of the following can be predict
Makovka662 [10]

If two different substances, with the same mass (1 gram) absorb the same amount of energy "the temperature of the substance with the lower specific heat will increase more than the one with a higher specific heat".

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8 0
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Lora (of mass 43.6 kg) is an expert skier. She starts at 3.6 m/s at the top of the lynx run, which is 67 m above the bottom. Wha
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Explanation:

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Hence,   E_{initial} = \frac{mv_{i}^{2}}{2} + mgh&#10;

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Now, final kinetic energy that will be at the bottom of the ski run is as follows.

Let,          E_{k} = E_{final}

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