Answer:
The track's angular velocity is W2 = 4.15 in rpm
Explanation:
Momentum angular can be find
I = m*r^2
P = I*W
So to use the conservation
P1 + P2 = 0
I1*W1 + I2*W2 = 0
Solve to w2 to find the angular velocity
0.240kg*0.30m^2*0.79m/s=-1kg*0.30m^2*W2
W2 = 0.435 rad/s
W2 = 4.15 rpm
W = mg = 350 newton
m = W/g = 350/9.8 = 35.71 kg
on mars
W = mg = 134 newton
g = W/m = 134/35.71 = 3.75 meters/second2
To solve this problem it is necessary to apply the concepts related to
conservation of energy, for this case manifested through work and kinetic energy.


Where,
F= Force (Frictional at this case
)
d= Distance

Where,
m = mass
v = velocity
Equation both terms,




Replacing with our values we have that


Therefore the shortest distance in which the truck can come to a halt without causing the crate to slip forward relative to the truck is 49.05m