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iren2701 [21]
3 years ago
15

What is the place value of 5 in 5,475,807,139

Mathematics
1 answer:
kkurt [141]3 years ago
8 0

Answer:

Billions

Step-by-step explanation:

You count from the right side to the left, the order being:

Ones

Tenths

Hundredths

Thousandth

Ten Thousandth

Hundred Thousandth

Millionth

Ten Millionth

Hundred Millionth

Billionth

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Alan saved $80 from his income in the month of March. In April, he decided to save 140% as much as he did in March. How much wil
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80×140%
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5 0
3 years ago
Read 2 more answers
Given f(x) = -3x + 5, find the value for f (7).
Lorico [155]

Answer:

-16.

Step-by-step explanation:

Given that f(x) = -3 times x + 5.

We need to find the value of f(7).

Hence we need to put x = 7 in the given function.

Hence f(7) = -3 times 7 + 5 = -16.

4 0
3 years ago
Fine the slope of the line graphed ?
strojnjashka [21]

Answer:

C. 2/5

Hope this helps!!!!!!!!

4 0
4 years ago
The hawaiian alphabet has 12 letters. How many permutations are possible for five of these letters
guajiro [1.7K]

Answer: The answer is 50980

Step by Step Explanation:

First, temporarily assume that two letters with I are different, call them i 1 and i 2. Three "a" are also called as a 1, a 2 and a 3, and two h as h 1 and h 2. Then there are 11 * 10 * 9 * 8 * 7 = 55440 possible "words" (one of 11 is the first letter, 10 is the second, and so on). But because equal letters do the same "words," some "words" were counted twice or more. We have to deduct the number of "parasitic" counts although it is fairly small. The words that counted more than once are divided into many disjoint sets: 1) with two I but without repetitions of a and h; 2) with two h but without repetitions of a and I 3) with two a but without repetitions of I and h; 4) with three a but without repetitions of I and h; 5) with two I and two a's; 6) two i's and tree a's; 7) two i's and two h's 8) two h's and two a's; 9) two h's and one tree. The first category includes terms counted twice and its scale is (5 * 4) * (6 * 5 * 4) = 2400 (the first I stays at one of the 5 positions, the second at one of the 4, then 11-2i-1h-2a=6). So we have 2400/2 = 1200 to subtract. Group 2 gives -600 as well, and group 3 also. Group 4 gives * (6 * 5) = 1800 (5 * 4 * 3), and the terms are counted 6 times, -300. Groups 5, 7 , 8: 5 * 4 * 3 * 2 * 6 = 720 and counted four times, therefore -180. Group 6 and 9: 5 * 4 * 3 * 2 * 1 = 120, with 12 counts, -10. Altogether -(1200 * 3 + 300 + 180 * 3 + 10 * 2) = -4460.The answer will be 55440-4460 = 50980.

3 0
4 years ago
One leg of a 45 - 45 - 90 triangle measures 10 inches. What is the length of the hypotenuse
djyliett [7]

Answer:

Therefore the length of the hypotenuse is 14.14 inches.

Step-by-step explanation:

Given:

The Triangle is of 45 -45 - 90

Length of one leg = 10 inches

To Find:

Length of the hypotenuse = ?

Solution:

The Triangle is of 45 -45 - 90 ..................Given

So For 45 - 45 - 90 Both the Legs of Triangle is SAME

i.e Longer leg = Shorter leg = 10 inches

Now in Right angle Triangle By Pythagoras Theorem we have

(\textrm{Hypotenuse})^{2} = (\textrm{Shorter leg})^{2}+(\textrm{Longer leg})^{2}

On substituting the values we get

Hypotenuse^{2}= 10^{2}+ 10^{2} \\\\Hypotenuse^{2}=200\\Square\ Rooting\ we\ get\\Hypotenuse=\sqrt{200}=10\sqrt{2}=10\times 1.414=14.14\ inches

Therefore the length of the hypotenuse is 14.14 inches.

5 0
3 years ago
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