Answer:
10 cm.
Step-by-step explanation:
We'll begin by calculating the area of the small bubble. This can be obtained as follow:
Radius (r) = 5 cm
Area (A) =?
Since the bubble is circular in nature, we shall use the formula for area of circle to determine the area of the bubble. This is illustrated below:
A = πr²
A = π × 5²
A = 25π cm²
Next, we shall determine the total area of the small bubbles. This can be obtained as follow:
Area of 1 bubble = 25π cm²
Therefore,
Area of 4 bubbles = 4 × 25π cm²
Area of 4 bubbles = 100π cm²
Finally, we shall determine the radius of the large bubble. This can be obtained as follow:
Area of large bubble = total area of small bubbles = 100π cm²
Radius (r) =?
A = πr²
100π = πr²
100 = r²
Take the square root of both side
r = √100
r = 10 cm
Thus, the radius of the large bubble is 10 cm
9514 1404 393
Answer:
4
Step-by-step explanation:
The geometric mean of two numbers is the square root of their product.
√(8·2) = √16 = 4
The geometric mean of 8 and 2 is 4.
__
The geometric mean of n numbers is the n-th root of their product.
Answer:
B
Step-by-step explanation:
Answer:
The answer is D.
An event D is said to be independent of another event.
we'll do the same as before, turning the mixed fractions to improper and do the division, keeping in mind that is simply asking how many times 1⅕ goes into 8⅔.
![\bf \stackrel{mixed}{8\frac{2}{3}}\implies \cfrac{8\cdot 3+2}{3}\implies \stackrel{improper}{\cfrac{26}{3}}\\\\\\\stackrel{mixed}{1\frac{1}{5}}\implies \cfrac{1\cdot 5+1}{5}\implies \stackrel{improper}{\cfrac{6}{5}}\\\\[-0.35em]\rule{34em}{0.25pt}\\\\\cfrac{26}{3}\div \cfrac{6}{5}\implies \cfrac{26}{3}\cdot \cfrac{5}{6}\implies \cfrac{130}{18}\implies \cfrac{126+4}{18}\implies \cfrac{126}{18}+\cfrac{4}{18}\\\\\\\boxed{7+\cfrac{4}{18}}\implies 7\frac{4}{18}](https://tex.z-dn.net/?f=%20%5Cbf%20%5Cstackrel%7Bmixed%7D%7B8%5Cfrac%7B2%7D%7B3%7D%7D%5Cimplies%20%5Ccfrac%7B8%5Ccdot%203%2B2%7D%7B3%7D%5Cimplies%20%5Cstackrel%7Bimproper%7D%7B%5Ccfrac%7B26%7D%7B3%7D%7D%5C%5C%5C%5C%5C%5C%5Cstackrel%7Bmixed%7D%7B1%5Cfrac%7B1%7D%7B5%7D%7D%5Cimplies%20%5Ccfrac%7B1%5Ccdot%205%2B1%7D%7B5%7D%5Cimplies%20%5Cstackrel%7Bimproper%7D%7B%5Ccfrac%7B6%7D%7B5%7D%7D%5C%5C%5C%5C%5B-0.35em%5D%5Crule%7B34em%7D%7B0.25pt%7D%5C%5C%5C%5C%5Ccfrac%7B26%7D%7B3%7D%5Cdiv%20%5Ccfrac%7B6%7D%7B5%7D%5Cimplies%20%5Ccfrac%7B26%7D%7B3%7D%5Ccdot%20%5Ccfrac%7B5%7D%7B6%7D%5Cimplies%20%5Ccfrac%7B130%7D%7B18%7D%5Cimplies%20%5Ccfrac%7B126%2B4%7D%7B18%7D%5Cimplies%20%5Ccfrac%7B126%7D%7B18%7D%2B%5Ccfrac%7B4%7D%7B18%7D%5C%5C%5C%5C%5C%5C%5Cboxed%7B7%2B%5Ccfrac%7B4%7D%7B18%7D%7D%5Cimplies%207%5Cfrac%7B4%7D%7B18%7D%20)
