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patriot [66]
3 years ago
13

Large reusable bottles cost $4 more than small ones. Eight large bottles cost $24 less than 12 small ones. How much does one sma

ll bottle cost?
Mathematics
1 answer:
ss7ja [257]3 years ago
5 0
A small bottle costs $14.

To solve the problem, the equation would be this:

 8(4+s)=12s-24

Let <em>s </em>represent a small bottle. Since one large bottle is $4 more than a small one, you would write out <em>(4+s)</em>. Then, multiply it by 8 to find one side of the equation, and get <em>8(4+s)</em>. To write out the right side of the equation, you would write out <em>12s </em>to represent 12 small bottles, and <em />subtract <em />24 from that to represent that 8 large bottles is $24 less than 12 small ones. 

Then, proceed to solve the equation to get the answer of <em>s=14</em>. Because a small bottle is $14, you can check your work by substituting the 14 in replace of <em>s</em>. <em />
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How do you solve this?
solong [7]

It looks like your equations are

7M - 2t = -30

5t - 12M = 115

<u>Solving by substitution</u>

Solve either equation for one variable. For example,

7M - 2t = -30   ⇒   t = (7M + 30)/2

Substitute this into the other equation and solve for M.

5 × (7M + 30)/2 - 12M = 115

5 (7M + 30) - 24M = 230

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Now solve for t.

t = (7 × (80/11) + 30)/2

t = (560/11 + 30)/2

t = (890/11)/2

t = 445/11

<u>Solving by elimination</u>

Multiply both equations by an appropriate factor to make the coefficients of one of the variables sum to zero. For example,

7M - 2t = -30   ⇒   -10t + 35M = -150 … (multiply by 5)

5t - 12M = 115   ⇒   10t - 24M = 230 … (multiply by 2)

Now combining the equations eliminates the t terms, and

(-10t + 35M) + (10t - 24M) = -150 + 230

11M = 80

M = 80/11

It follows that

7 × (80/11) - 2t = -30

560/11 - 2t = -30

2t = 890/11

t = 445/11

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